Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
b
Step-by-step explanation:
Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft
step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft
</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>
the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>
</span>
Answer:
solve using long division.
75/4
what is the largest whole number smaller than 75 that 4 can go into?
72.
how many times can 4 go into 72?
18.
so then subtract 72 from 75 to get 3.
the new equation is
3/4
how many times can 3 go into 4?
0.75 times.
so add the 2 answers to get
18.75
4 can go into 75 18.75 times.
Answer:
The twentieth term is 50.
Step-by-step explanation:
The equation that describes the arithmetic sequence describes it's "general term", which means that all the numbers in that sequence must follow that equation. For instance, if we want to find the first term of the sequence we must make a = 1 and we have:
a1 = 3*1 - 10
a1 = -7
Therefore to find the twentieth term we need to make n equal to 20. This is done below:
a20 = 3*20 - 10
a20 = 60 - 10
a20 = 50
The twentieth term is 50.
