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3 years ago

What are the values of each variable

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

3 0

Answer:

Step-by-step explanation:

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Alex is tracking how many computers he can fix in an afternoon. He listed the number of computers fixed per hour in the followin

Artist 52 [7]

Answer:
This is a linear function because there is a common difference of 4
⇒ 2nd answer
Step-by-step explanation:
- In the linear function there is a common difference between each two
consecutive data
- In the exponential function there is a common ratio between each two
consecutive data
- Lats check the data in the data in the table
(x) === 1 ⇒ 2 ⇒ 3
f(x) === 4 ⇒ 8 ⇒ 12
∵ x has consecutive numbers 1 , 2 , 3
∵ 8 - 4 = 4
∵ 12 - 8 = 4
∴ f(x) has a common difference 4
∵ 8 ÷ 4 = 2
∵ 12 ÷ 8 = 1.5
∴ f(x) has no common ratio
∴ The table represents a linear function with common difference 4
This is a linear function because there is a common difference of 4

6 0

3 years ago

16 is 4% of what number?

IrinaK [193]

16 is 4% of 400

Change the percentage into a decimal by dividing the decimal over 100:
$\frac{4}{100} = 0.04$

Divide 16 by the decimal (0.04):
$16 \div 0.04 = 400$

3 0

3 years ago

Help please ?

grandymaker [24]

Answer:

i think it may be "A" but i may be wrong sorry if im wrong

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Is q = 4b proportional or non proportional

mart [117]

It is proportional because it has a direct relationship.

5 0

3 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

3 years ago