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svet-max [94.6K]
3 years ago
5

What are the values of each variable

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

Step-by-step explanation:

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A rectangular prism has a length of 8 in., a width of 4 in., and a height of 2 1/4 in.
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It would need 288 cubes to fill up the prism.
7 0
3 years ago
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What is the length of AC¯¯¯¯¯
Nutka1998 [239]

Answer: AC=12 cm

Step-by-step explanation:

To  solve this problem you must apply the law of sines, as you can see below:

\frac{a}{sinA}=\frac{b}{sinB}

Where:

a=13

A=85.2°

B=71.6°

Therefore, you must solve for b, then, you obtain that the lenght AC asked in the problem above is:

b={sinB}*\frac{a}{sinA}\\b=\frac{sin(71.6)*13}{sin(85.2)}\\b=12

5 0
3 years ago
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What does x = ? 1 ÷ 11/2 = x
Yanka [14]

Answer:

x = 2/11

Step-by-step explanation:

1 ÷ 11/2 = x

1 · 2/11 = x (Used the opposite reciprocal and changed to multiplication. This is the same as dividing with the original fraction.)

2/11 = x

7 0
3 years ago
What’s the answer? Because am having a hard time with this math problem.
Studentka2010 [4]

9514 1404 393

Answer:

  34.5 square meters

Step-by-step explanation:

We assume you want to find the area of the shaded region. (The actual question is not visible here.)

The area of the triangle (including the rectangle) is given by the formula ...

  A = 1/2bh

The figure shows the base of the triangle is 11 m, and the height is 1+5+3 = 9 m. So, the triangle area is ...

  A = (1/2)(11 m)(9 m) = 49.5 m^2

The rectangle area is the product of its length and width:

  A = LW

The figure shows the rectangle is 5 m high and 3 m wide, so its area is ...

  A = (5 m)(3 m) = 15 m^2

The shaded area is the difference between the triangle area and the rectangle area:

  shaded area = 49.5 m^2 - 15 m^2 = 34.5 m^2

The shaded region has an area of 34.5 square meters.

7 0
2 years ago
The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

T19 = $45,4120

n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

y = 20500 + 481800

y = $502300

6 0
3 years ago
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