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sweet [91]
3 years ago
5

How do you solve the following for x?

Mathematics
2 answers:
EleoNora [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Is called a letter that stands for the number

Pachacha [2.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

√10x - 1 = 7

Square both sides,

10x - 1 = 7²

10x - 1 =  49

10x = 49 + 1

10x = 50

x = 50/10

x=5

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What expression can be used for estimating 868 divided by 28
weeeeeb [17]
868 is about 870, and 28 is about 30, so your expression would be 870 divided by 30 which would be 29 and the actual answer is 31, so your estimate would be close to your actual answer.
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Junnie walked for 2.5 hours at a speed of 3.miles per hour. How far did Junnie walk?
Leona [35]

Answer:

7.5 miles

Step-by-step explanation:

2.5 times 3

hope this can help you :-P

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PLEASE HALP ME! ( WILL MARK BRAINLIEST! Thank you! ;)
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Answer: 1/20

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Decimal Fraction Percentage

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3 years ago
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Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced
Butoxors [25]

Answer:

1) \chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

2) df = c-1 = 2-1

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

And if we replace we got:

\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

Part 2

For this case the degreed of freedom are given by:

df = c-1 = 2-1

Where c represent the number of categories c=2

And we can calculate the p value given by:

p_v = P(\chi^2_{1} >2)=0.157

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

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Vanyuwa [196]
You just combine like terms
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