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sweet [91]
3 years ago
5

How do you solve the following for x?

Mathematics
2 answers:
EleoNora [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Is called a letter that stands for the number

Pachacha [2.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

√10x - 1 = 7

Square both sides,

10x - 1 = 7²

10x - 1 =  49

10x = 49 + 1

10x = 50

x = 50/10

x=5

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PWEASE HELP IF YOUBARE GOOD AT MATH
Novosadov [1.4K]
<h3>Answer: 2</h3>

=========================================================

Explanation:

The function f(x) = -4x+1 is the same as y = -4x+1 where y = f(x)

Compare this to y = mx+b and we see the slope here is m = -4

---------

Now let's find the slope of g(x)

use the slope formula with any two rows you want. I'll pick on the last two rows.

m = (y2-y1)/(x2-x1)

m = (21-9)/(3-1)

m = 12/2

m = 6 is the slope of g(x)

---------

From here, we add the two slope values

(slope of f)+(slope of g) = -4+6 = 2

3 0
3 years ago
Is -2.75 greater than or less than -2.5
Alex

-2.75 is less then -2.5 or -2.50. For negatives only, if the number is less it is greater, and if a number is greater it is less.

Brainliest please!

3 0
3 years ago
Which of the following expressions represent the distance between - 3 and 5 on the number line?
yuradex [85]

Answer:

59

Step-by-step explanation:

apavaugaqboabeua j qbsioaveiabwnqpanwbgaoave giuuajwbaiave ia k w

3 0
3 years ago
How would I find the value of X in this equation
slava [35]
Sum of angles In all triangles are 180....line DAC is horizontal and therefore is 180 degrees ....so minus 180 degrees from 105 and you get 75 degrees....and since the sum of all angles in a triangle is 180...add 75 and 67 which would be 142 degrees ...then minus 142 from 180 degrees to get 38 degrees for x
4 0
3 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
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