Find an ordered triple to represent u in u=6w+2z if v=(4,-3,5), w=(2,6,-1), and z=(3,0,4).

How do you calculate surface area of trapezium with an angle

Kay [80]

Answer: There are eight steps and two methods. I will be showing you one of them. If you're wondering, I am in 7th grade. I go to K12 online school.

Step-by-step Explanation: 1. Add together the lengths of the bases. The bases are the 2 sides of the trapezoid that are parallel with one another. If you aren’t given the values for the base lengths, then use a ruler to measure each one. Add the 2 lengths together so you have 1 value.[1]

For example, if you find that the top base (b1) is 8 cm and the bottom base (b2) is 13 cm, the total length of the bases is 21 (8 cm + 13 cm = 21 cm, which reflects the "b = b1 + b2" part of the equation).
2. Measure the height of the trapezoid. The height of the trapezoid is the distance between the parallel bases. Draw a line between the bases, and use a ruler or other measuring device to find the distance. Write the height down so you don’t forget it later in your calculation.[2]

The length of the angled sides, or the legs of the trapezoid, is not the same as the height. The leg length is only the same as the height of the leg is perpendicular to the bases.

3. Multiply the total base length and height together. Take the sum of the base lengths you found (b) and the height (h) and multiply them together. Write the product in the appropriate square units for your problem.[3]

In this example, 21 cm x 7 cm = 147 cm2 which reflects the "(b)h" part of the equation.

4. Multiply the product by ½ to find the area of the trapezoid. You can either multiply the product by ½ or divide the product by 2 to get the final area of the trapezoid since the result will be the same. Make sure you label your final answer in square units.[4]

For this example, 147 cm2 / 2 = 73.5 cm2, which is the area (A).

7 0

2 years ago

Solve the system of equations by the substitution method

slava [35]

Answer:

x=0.5

y = 10.5

Step-by-step explanation:

y = 3x + 7

y = 5x + 8

3x + 7 = 5x + 8

3x - 5x= 8 - 7

2x = 1

x= 1/2

x=0.5

y = 5x + 8

y = 5(0.5) + 8

y = 2.5 + 8

y = 10.5

8 0

3 years ago

Given the following formula, solve for I. P = 2(1 + 6) PLEASE HELP!!!

Pepsi [2]

Step-by-step explanation

Here ...I'm not too sure about the question as you have written

P = 2 ( 1 + 6 ) and ask to solve for L ...

.So I guess the question you have written is wrong .. ...and I guess there should be L in the place of 1.

...So let me correct the question....

P = 2 ( l + 6 )

P = 2l + 12

P - 2l = 12

- 2l = 12 - P

- 2l = - P + 12

Change the sign of both side of the equation...

2l = P + 12

divide both side by the same number...

L = ( P + 12 ) ÷ 2

$l = \frac{1}{2} p - 12 \times \frac{1}{2} \\$

Calculate the product of rational numbers...

$l = \frac{1}{2} p - 6 \\$

5 0

2 years ago

A $40.00 shirt is on sale for 35% off. How much will I save?

mina [271]

Answer:

You will save $14.00

Step-by-step explanation:

If the shirt is 35% off, it means that you will effectively save 35% of the price. 35% of the price in this case is 35% of 40, which is $14.00

5 0

3 years ago

Reflection Over Parallel Lines Please complete the attached reflection. Thanks!

Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

4 0

3 years ago