All categories

3 years ago

How do u write 2.51 in word form and expanded form?

Mathematics

2 answers:

Wittaler [7]3 years ago

4 0

Word form . . . two and fifty-one hundredths

Expanded form . . . 2.00 + 0.50 + 0.01

EastWind [94]3 years ago

3 0

The <em>correct answers</em> are:

In word form - "Two and fifty-one hundredths." In expanded form - 2 + 0.5 + 0.01.

Explanation:

To write a decimal in word form, we write out the words we would say as we read the decimal. When we read a decimal, we read the whole number before the decimal. This is "two." The decimal is read as "and." After this, we read the digits behind the decimal as a group; 51 would be read as "fifty-one", and since 1 is in the hundredths place, it is "fifty-one hundredths."

To write a number in expanded form, we separate the digits by place value. 2 is in the ones place, so it equals 2. 5 is in the tenths place, so it equals 0.5. 1 is in the hundredths place, so it equals 0.01. Together this gives us:

2 + 0.5 + 0.01.

You might be interested in

A savings account accrues interest at a rate of 3.0% yearly. If someone opens an account with $2,500, how much money would the a

stira [4]

<span>2500(1.03)^5 that's the equation .
which means it would be 2,898.18</span>

6 0

3 years ago

Evaluate each expression a3 for a=5

nadezda [96]

I'm assuming you meant to say a^3. If so, then

a^3 = a*a*a
a^3 = 5*5*5
a^3 = 125

4 0

3 years ago

The ball used in a soccer game may not weigh more than 16 ounces or less

Liono4ka [1.6K]

In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
x = 12.5 ounces

The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
x = 14.5 ounces

From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.

3 0

3 years ago

A supervisor records the repair cost for 14 randomly selected refrigerators. A sample mean of $79.20 and standard deviation of $

Nitella [24]

Answer:

( $74.623, $83.777)

The 90% confidence interval is = ( $74.623, $83.777)

Critical value at 90% confidence = 1.645

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $79.20

Standard deviation r = $10.41

Number of samples n = 14

Confidence interval = 90%

Using the z table;

The critical value that should be used in constructing the confidence interval.

z(α=0.05) = 1.645

Critical value at 90% confidence z = 1.645

Substituting the values we have;

$79.20+/-1.645($10.42/√14)

$79.20+/-1.645($2.782189528308)

$79.20+/-$4.576701774067

$79.20+/-$4.577

( $74.623, $83.777)

The 90% confidence interval is = ( $74.623, $83.777)

5 0

3 years ago

I need help with my math homework

Rashid [163]

Hello. This is how to do it...

Step 1: Figure out what "N" means.

Step 2: Multiply whatever "N" means by -4

Step 3: Subtract -4 times "n"

Hope this will help! Im sorry if i was a pain tho...

5 0

3 years ago