Answer:9.13
Step-by-step explanation:There are three lines from the center to the sides. So they are all the same. you can see that the radius is 8 from one of the sides. You can find the area of the big triangle by knowing that 2 of the sides are 8 and 360-270=90 and that is a right triangle so we can use the pythagorean theorem to find the hypotenuse. 8^2+8^2=√128. And we can find the area by doing (8^2+8^2)/2=32 so each triangle is 16 units^2. To find out the lengths of the left triangle we have (.5*√128)^2=√32. So 8^2-32=x² x=√32. if the radius is 8 and the one side of the radius is √32 it would be 8-√32. and the other line touching the shaded area it √128 so we can say that the area of the non-little circle is the area of the whole circle-the almost circle. The area of the whole circle it 8^2*pi≈201.06. The area of the almost circle is 201.06*.75=150.79 because 270/360=.75 plus the area of the triangle (32) so the area is 182.79. So the area of the little thing is 201.06-182.79=18.27 divided by 2 =9.13
Answer:
6
Step-by-step explanation:
To solve this problem, you simply plug 2 in for x in the equation of f(x):
f(2) = 2 + 4 = 6
Thus, the answer is 6.
Hope this helps!
Answer:
See below in bold.
Step-by-step explanation:
1. The 3 angles in a triangle add up to 180 degrees.
So x = 180 - (55 + 25)
= 180 - 80
= 100 degrees.
2. The 4 angles in a quadrilateral add up to 360 degrees,, so
3x + 127 + 54 + 119 = 360
3x + 300 = 360
3x = 360 - 300
3x = 60
x = 20 degrees.
3. Exterior angle
= 94 + 42
= 136 degrees.
Yes. AB is parallel to line CD. The “same side interior angles” theorem applies to this problem. I hope this helps you
