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olga2289 [7]
3 years ago
13

What is the factorization of the polynomial 2x^2+28x+98

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

Step-by-step explanation:

hello : answer B

because : 2(x+7)(x+7) = 2(x²+7x+7x+49) = 2(x²+14x+49) = 2x²+28x+98

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Yuliya22 [10]

Answer:Gary-18 years brother-10 years

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2nd case:......

3rd case:.....

4th case:brother:4 years gary:12 yrs=>after 6 yrs:brother=10 yrs gary=18 yrs=>18-10=8

8 0
4 years ago
Compare the y-intercepts and rates of change of the following items.
kotykmax [81]

Answer:

D.   They have the same slope ( rate of change) and the same y-intercept.

Step-by-step explanation:

I  y = 1.2x + 0.4.

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3 0
4 years ago
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Given the function f(x) = 2x + 2, what is the value of x if f(x) = 6?
Marrrta [24]
X will be equal to 4
4 0
3 years ago
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A company has 2 machines that manufacture widgets. An older machine manufactures 25% defective widgets, while the new machine ma
Bingel [31]

Answer:

73.90%

Step-by-step explanation:

Let Event D=Defective,  D' = Non Defective

Let Event N=New Machine, N' = Old Machine

From the given information:

P(D|N')=0.25\\P(D|N)=0.09\\P(N)=0.7\\P(N')=0.3

We are required to calculate the probability that a widget was manufactured by the new machine given that it is non defective.  

i.e. P(N|D')

P(D'|N')=1-P(D|N')=1-0.25=0.75\\P(D'|N)=1-P(D|N)=1-0.09=0.91

Using Baye's Law of conditional Probability

P(N|D')=\dfrac{P(D'|N)P(N)}{P(D'|N)P(N)+P(D'|N')P(N')} \\=\dfrac{0.91*0.7}{0.91*0.7+0.75*0.3}\\ =0.73897\\\approx 0.7390

Therefore given that a selected widget is non-defective, the probability that it was manufactured by the new machine is 73.9%.

5 0
3 years ago
74,987.45 x 6,756.2 + 67,893.64 = ?
zysi [14]

Answer:

esa respuesta está bien

4 0
3 years ago
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