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koban [17]
3 years ago
15

I'm really bad at math

Mathematics
1 answer:
Lynna [10]3 years ago
6 0
What chapter is this?

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The total number of faculty members is 442. The school reported that it had 6 professors to every 11 lecturers. How many of each
Musya8 [376]
The school has 156 professors and 286 lectures
5 0
3 years ago
Select all the expressions equivalent to (4x⁵)(5x⁶).
Liula [17]

Step-by-step explanation:

= 4 {x}^{5}  \times 5 {x}^{6}

= (4 \times 5) {x}^{5 + 6}

= 20 {x}^{11}

3 0
3 years ago
True or False? A triangle with two congruent angles can never be scalene. A. True B. False
Wewaii [24]
True, because a triangle with 2 congruent sides/angles is ALWAYS an isosceles triangle.
Hive a nice day! ♪
8 0
3 years ago
Read 2 more answers
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
3 years ago
Which are sums of perfect cubes? Check all that apply.
vichka [17]
I think these are the sums of perfect cubes. 

A = (2x²)³ + (3)³
B = (x³)³ + (1)³
D = (x²)³ + (x)³
E = (3x³)³ + (x^4)³

5 0
3 years ago
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