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zheka24 [161]
3 years ago
12

On a average day a horse might drink 50 la sheep might drink 4 l and a chicken might drink 200ml how much water would a farm wit

h 3 horses 15 sheep and 12 chickens need for a day
Mathematics
1 answer:
horsena [70]3 years ago
8 0
Horse- 50l
sheep-4l
chicken-200ml

first you have to convert all the symbols into one, so we'll convert liters into milliliters,
 
1000ml=1l

horse= 50 ×1000=50000ml
sheep=4×1000=4000ml
chicken= 200ml

so now we have to multiply them by the number of animals,

h=50000ml×3=150000ml
s=4000×15=60000ml
c=200×12=2400ml

now add them together,

150000+60000+2400=212400ml

convert it into litres, 
212400÷1000=212.4l

answer= 212.4 l 
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The sketch of the parabola is attached below

We have the focus (a,b) = (2, -0.5)
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The directrix, c at y=-1.5

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; (2, -0.5) and (x,y).
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Step 2
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Step 3
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Therefore, we can write the expression in the remainder quotient form as,

x^{2}-2+\frac{20}{x+7}

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Answer:

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Step-by-step explanation:

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