The transformed points of the triangle ABC are $A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$ , $B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$ , $C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

$A' (x,y) = \frac{1}{2}\cdot (1,1)$

$A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$

$B' (x,y) = \frac{1}{2}\cdot (9,1)$

$B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$

$C'(x,y) = \frac{1}{2}\cdot (1,9)$

$C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

7 0

3 years ago

-8x + 10y + 16x - 2y<br> Simplify and show work

HACTEHA [7]

Answer:

8x+8y

Step-by-step explanation:

7 0

3 years ago

Help plz:)))I’ll mark u Brainliest

DerKrebs [107]

Answer:

The answer to the question provided is letter D.

8 0

3 years ago