Answer
Find out the value of g(3) by using the function g(x) = x² + 2 given in the question .
To proof
The function given in the question is
g(x) = x² + 2
Take x = 3
put x = 3 in the g(x) = x² + 2
than it becomes
g(3) = 3² + 2
solving the above
we get
g(3) = 9 + 2
g(3) = 11
Thus g(3) = 11 and option (c) is correct .
Hence proved
For the first question, use slip and slide or the box method to get (x-2)(2x-3)
Do the same for the second question to get (3x-4)(x+1)
Answer:
12 which is on C
Step-by-step explanation:
use pathogoras theorem
a^2+b^2=c^2
16^2+b^2=20^2
256+b^2=400
b^2=400-256
b^2=144
b= square root of 144
b= 12
Answer:
x= 1 or x=7
Step-by-step explanation:
2 x 2− 16 x + 14 =0
2 (x−1) (x−7)=0
x−1=0 or
x−7=0
x=1 or x=7
