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inn [45]
3 years ago
6

What is the range of the data set 125,236, 185, 125, 201, and 155?​

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0

Answer:

111

Step-by-step explanation:

<em>Range </em><em>is</em><em> the</em><em> </em><em>difference</em><em> between</em><em> </em><em>the</em><em> </em><em>highest </em><em>and </em><em>the</em><em> </em><em>lowest </em><em>term</em><em>.</em><em> </em>

<em>Here </em><em>highest </em><em>term </em><em>is </em><em>2</em><em>3</em><em>6</em><em> </em><em>and </em><em>lowest </em><em>term </em><em>is </em><em>1</em><em>2</em><em>5</em><em>.</em><em> </em>

<em>Ran</em><em>g</em><em>e </em><em>-</em><em>-</em><em>></em><em> </em><em>2</em><em>3</em><em>6</em><em>-</em><em>1</em><em>2</em><em>5</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>1</em><em>1</em>

<h2><em><u>Please</u></em><em><u> </u></em><em><u>mark </u></em><em><u>me </u></em><em><u>Brainlist</u></em><em><u> and</u></em><em><u> </u></em><em><u>follow </u></em><em><u>me </u></em><em><u>(✷‿✷)</u></em></h2>
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EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


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M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


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M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

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