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kogti [31]
3 years ago
14

A bag contains 8 red marbles, 3 blue marbles, and 1 green marble. What is the probability that a randomly selected marble is not

blue? ​
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
4 0

Answer:

.75

Step-by-step explanation:

8 red marbles, 3 blue marbles, and 1 green marble = 12 marbles

P( not blue) = marbles that are not blue / total

                     =(8red+1 green) / 12

                     =9/12

                      = 3/4

                       .75

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Solve (x + 2 < 5) ∩ (x - 7 > -6).
mihalych1998 [28]

Answer:

<h2>1. {x | 1 < x < 3}</h2>

Step-by-step explanation:

x + 2 < 5           <em>subtract 2 from both sides</em>

x + 2 - 2 < 5 - 2

x < 3

x - 7 > -6        <em>add 7 to both sides</em>

x > 1

From x < 3 and x > 1 we have 1 < x < 3

7 0
3 years ago
I have no idea how to solve??
kupik [55]

120 = (1/3)b(8) =

B = 120/ (1/3)8

B = 120/ 2 2/3

B = 45

3 0
3 years ago
What is the mathematical relationship between the atomic radius (r) and the lattice parameter (a0) in the BCC structure? a. b. c
ryzh [129]

Answer: Lattice parameter, a = (4R)/(√3)

Step-by-step explanation:

The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.

The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.

If the diagonal of the base of the unit cell = x

(a^2) + (a^2) = (x^2)

x = a(√2)

Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.

Let the diagonal across the cube be y

Pythagoras theorem,

(a^2) + ((a(√2))^2) = (y^2)

(a^2) + 2(a^2) = (y^2) = 3(a^2)

y = a√3

But the diagonal through the cube = 4R (evident from the image in the first attachment)

y = 4R = a√3

a = (4R)/(√3)

QED!!!

8 0
3 years ago
Read 2 more answers
Please help me. This is due today
sattari [20]

Answer:

it answer is 3 because it is trigonometry

3 0
3 years ago
Diego is solving this system of equations:
USPshnik [31]

The solutions of the equations are x = 1 and y = 2

The system of equations are

4x + 3y = 10

-4x + 5y = 6

Here we have to use the elimination method. Eliminate the x term and find the value of y term

Add both equation

3y + 5y = 10 +6

Add the like terms

8y = 16

y = 16 / 8

Divide  the terms

y = 2

Substitute the value of x in the first equation

4x + 3y = 10

4x + 3×2 =  10

Multiply the terms

4x + 6  = 10

4x = 10 - 6

4x = 4

x = 4 / 4

Divide the terms

x = 1

Hence, the solutions of the equations are x = 1 and y = 2

Learn more about elimination method here

brainly.com/question/14619835

#SPJ1

7 0
2 years ago
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