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stealth61 [152]
3 years ago
6

Find the value of the expression |2x−8| where x=−2.5; 0; 4; 5; 9.5.

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

The absolute value |x| returns the "positive version" of a number. In other words, if x is already positive, then |x|=x. Otherwise, if x is negative, then the absolute value changes its sign, so that it returns positive: |x|=-x.

So, in this case, we have to plug the required values for x in the expression 2x-8. Then, if the result is positive we're ok, otherwise we discard the negative sign.

We have:

x=-2.5 \implies |2x-8| = |-5-8|=|-13|=13

x=0 \implies |2x-8| = |0-8|=|-8|=8

x=4 \implies |2x-8| = |8-8|=|0|=0

x=5 \implies |2x-8| = |10-8|=|2|=2

x=9.5 \implies |2x-8| = |19-8|=|11|=11

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To solve this question, we can start to set up an equation using what the question is telling us. Since we don't know what the number is, let's make it equal to x.

The phrase "5 times a number" means that we're multiplying our unknown, x, by 5. That is equal to 5x. 9 less than that would be 5x - 9. Since we know that it's equal to -30, we can solve.

5x - 9 = -30

Get all terms with x on one side and the constants on the other

5x - 9 +9 = -30 + 9

Simplify

5x = -21

Now, we can divide both sides by 5 to get our answer of x = -\frac{21}{5}

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x = 20 degrees.

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Transform the Cartesian (rectangular) equation to a polar equation: x = -9. The selected answer is incorrect.
nika2105 [10]

Answer:

Solution : Option C

Step-by-step explanation:

We have the equations r² = x² + y², x = r cos(θ), and y = r sin(θ) that can be used to solve this problem. In this case we only need the second two equations (  x = r cos(θ), and y = r sin(θ) ) as we don't need to apply the concept of circles etc here.

Given : x = - 9,

( Substitute r cos(θ) for x )

r cos(θ) = - 9,

r = - 9 / cos(θ)

( Remember that sec is the reciprocal of cos(θ). Substitute sec for 1 / cos(θ) )

r = - 9 sec(θ)

Therefore the third option is the correct solution.

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3 years ago
The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti
max2010maxim [7]
Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
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In this simultaneous equation we see that y is equal to both the expressions. So,
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Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
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