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Bess [88]
3 years ago
11

Tell whether the following sequence is geometric or not. If geometric find r

Mathematics
2 answers:
Afina-wow [57]3 years ago
6 0

Answer:

not geometric because of the 4 at the beginning

PolarNik [594]3 years ago
3 0

Answer:

  • No

Step-by-step explanation:

We can observe the difference of terms is constant:

  • d = 1/3

The sequence is arithmetic, not geometric.

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Blackcap birds (Sylvia atricapilla) migrate out of Germany before wintertime. Prior to the 1960s, all members of a particular bl
UkoKoshka [18]

Answer:

D- The blackcaps will begin nesting at their wintering sites in Spain or the United Kingdom, resulting in a larger blackcap population migrating back to Germany after the breeding season has ended.

Step-by-step explanation:

By the inhabitants of Spain and the United Kingdom placing feeders out for the blackcaps, the birds in their nesting sites during the winter will have food to eat, meaning a bigger population of the Blackcaps when they return to their main home in Germany.

This best predicts the effect on the blackcap population if humans in the United Kingdom continue to place food in feeders during the winter.

8 0
3 years ago
The square root of 52 is between which two consecutive Integers?
Murrr4er [49]
The answer is 7 and 8
7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP! D:
artcher [175]

The solution to a system of equations is the point where the 2 lines of a graph cross each other.

On the pictured graph, the lines cross each other at x = -6 and Y = -2.

The answer would be (-6,-2)

8 0
3 years ago
Which answer best describes the complex zeros of the polynomial function?
marysya [2.9K]

<u>Answer-</u>

<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>

<u>Solution-</u>

The given polynomial is,

f(x)=x^3-x^2+6x-6

The zeros of the polynomials are,

\Rightarrow f(x)=0

\Rightarrow x^3-x^2+6x-6=0

\Rightarrow x^2(x-1)+6(x-1)=0

\Rightarrow (x^2+6)(x-1)=0

\Rightarrow (x^2+6)=0,(x-1)=0

\Rightarrow x=\sqrt{-6},\ x=1

\Rightarrow x=1,\ \pm \sqrt6i

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0
3 years ago
Can somebody please solve question 11 for me?
Amanda [17]
See photo for complete solution

8 0
3 years ago
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