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BigorU [14]
3 years ago
13

I need loads of help!! If you know how to do this please help me!!! It’s 6 and 7

Mathematics
1 answer:
dlinn [17]3 years ago
8 0
6- comedy and action
7- .75
You might be interested in
Helppp!!!!!
gladu [14]

Answer:

fyi b's answer has imaginary numbers in it...

Imaginary: 1 +\frac{\sqrt{2i} }{2 }    

Imaginary: 1 -  \frac{\sqrt{2i} }{2 }  

Step-by-step explanation:

2x^{2} - 4x -3 = 0

\sqrt{-4^{2} -4(2)(3)} = \sqrt{-8} ... the negative root will produce imaginary solutions

8 0
3 years ago
Read 2 more answers
Tan (angle B) using an exact expression in trigonometric ratios in right triangles
goblinko [34]
The value of the tangent of an angle is the ratio (opposite side) / (adjacent side).

Here you see that the opposite side (opposite to Angle B) is of length 5 and the adj. side has length 12.

Thus, the tan of Angle B is 5/12.  (answer)

4 0
4 years ago
PLEASE HELP ASAP!!<br> means a lot!!
egoroff_w [7]
The correct answer is:
B) \: y + 1 =  \frac{4}{3} (x - 9)
6 0
4 years ago
I need help pls and thank you
kobusy [5.1K]

Answer:

unbounded region

A feasible region that cannot be enclosed in a closed figure is known as an unbounded region. A feasible region is a set of all possible points of an optimization problem that satisfy the problem's constraints; feasible sets may be bounded or unbounded.

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP WITH GRAPH LAST QUESTION I NEED ​
SVETLANKA909090 [29]

Answer:

\sf g(x) = -1(x+3)^2 -2

Explanation:

\sf original \ graph:  \ y=-x^{2}

the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

\sf so \ new \ graph :

\sf y = a(x-h)^2 +k

\sf -6 = a(-1-(-3))^2 -2

\sf -6 = 4a -2

\sf 4a = -4

\sf a = -1

\sf equation:

\sf y = a(x-h)^2 +k

\sf y = -1(x+3)^2 -2

6 0
2 years ago
Read 2 more answers
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