Answer:
<em>Henry will buy 18 gift bags and 18 bows in 3 packs of gift bags and 2 packs of bows.</em>
Step-by-step explanation:
<u>Least Common Multiple (LCM)</u>
Is the smallest positive number that is a multiple of two or more numbers. To find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number.
Since Henry wants to buy the same number of gift bags and bows and they are sold in packs with different quantities, we must find the LCM between those numbers.
Gift bags are sold in packs of 6. Bows are sold in packs of 9.
List the prime factors of 6: 2,3
List the prime factors of 9: 3,3
Multiply: 2*3*3=18
The LCM is 18. This means Henry will buy 18 gift bags and 18 bows in 3 packs of gift bags and 2 packs of bows.
Answer:
Step-by-step explanation:
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ANSWER TO QUESTION 1
.
EXPLANATION
The function given to us is,

According to rational roots theorem,
are possible rational zeros of
.
We find out that,




Also




This implies that
are factors of
and hence
is also a factor.
We perform the long division as shown in the diagram.
Hence,
.
ANSWER TO QUESTION 2
Sketching the graph
We can see from the factorization that the roots
and
have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.
Also the root
has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.
Now we determine the position of the graph on the following intervals,









We can now use these information to sketch the function as shown in diagram
Answer: 
r=26
Step-by-step explanation:
Given: Mrs. Morton rewards her students on behave well by putting 3 marbles into a marble jar.
If the jar contains 24 marbles. and r represent the number of additional times the class is rewarded then the required equation will be

If we solve it, we will get the minimum the jar contains 24 marbles.
To solve equation, subtract 24 from both sides, we get

Hence, the minimum whole number of additional times they need to be rewarded so they can have a party=26