Answer:
x = 2 + sqrt(2) or x = 2 - sqrt(2) thus B. is your answer
Step-by-step explanation:
Solve for x over the real numbers:
4 x^2 - 16 x + 8 = 0
Hint: | Write the quadratic equation in standard form.
Divide both sides by 4:
x^2 - 4 x + 2 = 0
Hint: | Solve the quadratic equation by completing the square.
Subtract 2 from both sides:
x^2 - 4 x = -2
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.
Add 4 to both sides:
x^2 - 4 x + 4 = 2
Hint: | Factor the left-hand side.
Write the left-hand side as a square:
(x - 2)^2 = 2
Hint: | Eliminate the exponent on the left-hand side.
Take the square root of both sides:
x - 2 = sqrt(2) or x - 2 = -sqrt(2)
Hint: | Look at the first equation: Solve for x.
Add 2 to both sides:
x = 2 + sqrt(2) or x - 2 = -sqrt(2)
Hint: | Look at the second equation: Solve for x.
Add 2 to both sides:
Answer: x = 2 + sqrt(2) or x = 2 - sqrt(2)
To solve this problem, we should set up an equation, letting the unknown value of miles that Ahmad drove be represented by the variable x. We can have our total price on one side of the equation, set equal to the base fee plus the number of miles Ahmad drove multiplied by the charge per mile (x). This equation is modeled below:
191.95 = 16.99 + 0.72x (remember that 72 cents in dollars is equal to 0.72!)
To solve this equation, we must get the variable x isolated on one side of the equation. To do this, we begin by subtracting 16.99 from both sides of the equation.
174.96 = 0.72x
Next, we must divide both sides of the equation by 0.72 to get rid of the coefficient on the variable x.
x = 243
Therefore, your answer is Ahmad drove the truck for 243 miles.
Hope this helps!
Answer:
Angle 1 = 90 degree
Angle 2 = 55 degree
Angle 3 = 35 degree
Step-by-step explanation:
A rhombus has four equal sides. Since the intersection angle of a rhombus is always 90 degree, angle 1 is 90 degree
Angle 3 = 180 degree - 90 degree - 55 degree = 35 degree
Angle 2 = 180 degree - 90 degree - 35 degree = 55 degree
126 = 2 · 3 · 3 · 7 I
t was easy.
Refer to the image that I attached to my answer.
According to the graphing calculator, the two equations have two points of intersections (the points where the different colored lines cross).
Happy Studying~