Answer:
C 200
Step-by-step explanation:
It does not appear to be LINEAR so
Start with :
pulse rate = y = 73e^kx
sub in x = .7 when y = 155
155 = 73 e^(.7 * k)
ln ( 155/73) = .7k
.75296567 = .7k
k = 1.07567
for x = 0.9 :
pulse rate = y = 73 e^(1.07567 * .9) = ~ 192 so I expect answer is 200
Answer:
a) Find the common ratio of this sequence.
Answer: -0.82
b) Find the sum to infinity of this sequence.
Answer: 2.2
Step-by-step explanation:
nth term in geometric series is given by ![4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{0.549} \\r = 0.82](https://tex.z-dn.net/?f=4%5C%20th%20%5C%20term%20%3D%20ar%5En-1%5C%5C-2.196%20%3D%204r%5E%7B4-1%7D%20%5C%5C-2.196%2F4%20%3D%20r%5E%7B3%7D%20%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B0.549%7D%20%5C%5Cr%20%3D%200.82)
where
a is the first term
r is the common ratio and
n is the nth term
_________________________________
given
a = 4
4th term = -2.196
let
common ratio of this sequence. be r
![4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{-0.549} \\r = -0.82](https://tex.z-dn.net/?f=4%5C%20th%20%5C%20term%20%3D%20ar%5En-1%5C%5C-2.196%20%3D%204r%5E%7B4-1%7D%20%5C%5C-2.196%2F4%20%3D%20r%5E%7B3%7D%20%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B-0.549%7D%20%5C%5Cr%20%3D%20-0.82)
a) Find the common ratio of this sequence.
answer: -0.82
sum of infinity of geometric sequence is given by = a/(1-r)
thus,
sum to infinity of this sequence = 4/(1-(-0.82) = 4/1.82 = 2.2
bangles scored 22 pts but don't know how much the ravens scored
Answer:
Step-by-step explanation:
here you go mate
step 1
-2(-4x-1)-x+3=−30 equation/Question
step 2
-2(-4x-1)-x+3=−30 distribute
7x+5=-30
step 3
7x+5=-30 subtract 5
7x=-35
step 4
divide
answer
x=-5