Step-by-step explanation:
Here are some equations





Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Answer:
The Estimate the number of students who took the scores between 82 and 98 = 16
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given data The scores on a math test are normally distributed with a mean μ = 74
standard deviation of Population
S.D (σ) = 8
Let 'x' be the random variable of Normal distribution
<u><em>case(i)</em></u>:- when x = 82


<u><em>case(ii)</em></u>:- when x = 98


The probability that test scores between 82 and 98.
P(82≤x≤98) = P(1≤z≤3)
= P(z≤3) - P(z≤1)
= 0.5+A(3)-(0.5+A(1))
= A(3) -A(1)
= 0.4986 - 0.3413
= 0.1573
<u><em>Final answer</em></u>:-
The Estimate the number of students who took the scores between 82 and 98
= 100 X 0.1573 = 15.73 ≅16
Answer:
HCF = 90
Step-by-step explanation:
Hope it Helps!!!