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Marina CMI [18]
3 years ago
15

Write an expression using the distributive property that can be used to find the quotient of 126÷7

Mathematics
1 answer:
lord [1]3 years ago
8 0
(100 divided. by 7) (20 divided by 7) ( 6 divided by 7)
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What are some equations with -3 as the solution?
erastovalidia [21]

Step-by-step explanation:

Here are some equations

{:}\longrightarrow\sf 3x+9=0

{:}\longrightarrow\sf x+3=0

{:}\longrightarrow\sf 6x+18=0

{:}\longrightarrow\sf x^2-9=0

{:}\longrightarrow\sf x+7=4

3 0
3 years ago
BD and AC are directors of .0 identify each Arc as a minor Arc interior Arts Elementary art
Maru [420]

Given BD and AC is a diameter of the circle:

We need to find the following:

1. measure of the arc BA

So,

the measure of the minor arc BA = 44

The measure of the major arc BA = 360 - 44 = 316

2. the measure of the arc ACB = 360 - 44 = 316

3. The arc BCD is a semicircle of the circle

So, the measure of the arc BCD = 180

5 0
1 year ago
At the school Fall Festival the students council sold soda at the fundraiser the table below shows the number of sodas they sold
mash [69]

Answer:

$4.80/2sodas

4.80/2=2.40

C. 2.40 per soda

3 0
3 years ago
The scores on a math test are normally distributed with a mean of 74 and a standard deviation of 8. The test scores range from 0
hram777 [196]

Answer:

The Estimate the number of students who took the scores between  82 and 98 = 16

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given data The scores on a math test are normally distributed with a mean μ = 74  

standard deviation of Population

                                               S.D (σ) = 8

Let 'x' be the random variable of Normal distribution

<u><em>case(i)</em></u>:-  when  x = 82

            Z = \frac{x-mean}{S.D}

           Z = \frac{82-74}{8} = 1

     

<u><em>case(ii)</em></u>:-  when  x = 98

            Z = \frac{x-mean}{S.D}

           Z = \frac{98-74}{8} = 3

The probability that test scores between 82 and 98.

P(82≤x≤98) = P(1≤z≤3)

                 = P(z≤3) - P(z≤1)

                 = 0.5+A(3)-(0.5+A(1))

                =  A(3) -A(1)

               = 0.4986 - 0.3413

               = 0.1573

<u><em>Final answer</em></u>:-

The Estimate the number of students who took the scores between  82 and 98

             = 100 X 0.1573 = 15.73 ≅16

           

7 0
3 years ago
Find the highest common factor (HCF) of 270 and 450.
lbvjy [14]

Answer:

HCF = 90

Step-by-step explanation:

Hope it Helps!!!

3 0
2 years ago
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