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kondaur [170]
3 years ago
12

A box plot was made to represent the number of matches won by 14 participants in a tennis tournament. The box plot had the box s

hifted to the right so that the left tail was much longer than the right tail. Based on the box plot, which conclusion is correct?
The mean and median of matches won are equal.

The mean of matches won is more than the median of matches won.

Most of the participants won many matches, but there were some participants who won very few matches compared to the others.

Most of the participants won very few matches, but there were some participants who won many matches compared to the others.
Mathematics
1 answer:
Zina [86]3 years ago
7 0
The right answer for the question that is being asked and shown above is that: "Most of the participants won many matches, but there were some participants who won very few matches compared to the others." <span>Based on the box plot, this conclusion is correct</span>
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Answer:

x= -5,5 and -3,3

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Naddika [18.5K]
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3 years ago
What is the percent equivalent of 3/2 using a pattern
olganol [36]
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3 years ago
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Help me with this questing plsss
docker41 [41]

Answer:

6.25n + 3.50

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Step-by-step explanation:

Break down the important information given in the problem.

The one-time delivery fee is 3.50. This is only paid one time an never again, making it the <u>constant</u>, a number that does not change.

Each lunch costs 6.25. This amount will increase depending on how many times Mr. Jackson orders lunches, "n" times. This number is the <u>rate</u> because it changes. The rate is attached to the variable.

If you add the amounts together, that is the total cost of ordering lunches.

6.25n + 3.50

(Reember expressions do not have the equal sign).

To find the cost of ordering 5 lunches, use the expression. Substitute "n" for 5 because "n" represents the number of lunches ordered.

6.25n + 3.50

= 6.25(5) + 3.50   Simplify by multiplying 5 and 6.25

= 31.25 + 3.50    Add the two values

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8 0
3 years ago
Simplify the complex fraction.
lilavasa [31]

Given:

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}

Step 2: Simplify the denominator

$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}

Step 3: Using step 1 and step 2

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}

Step 4: Using fraction rule:

$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}

$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}

Cancel the common factor r and t², we get

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Cancel the common factors 16 and 3 on both numerator and denominator.

           $=\frac{4 r^{2} \cdot 3 }{  5 t^2 }

           $=\frac{12 r^{2}  }{  5 t^2 }

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2}  }{  5 t^2 }

The simplified fraction is \frac{12 r^{2}  }{  5 t^2 }.

5 0
3 years ago
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