Assignment: 
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Answer: 
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Explanation: 
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Note: 
[ Step One ] Apply Rule - (-a) = a
[ Step Two ] Add
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Answer:
the angle between their paths is <em>100.8°</em>
Step-by-step explanation:
From the given information, you can construct a triangle, just like the one in the figure.
We will use the <em>Cosine Rule</em> which is:
c² = b² + a² - 2 b c cos(θ)
where
- c = 16 miles
- b = 8 miles
- a = 12 miles
Therefore,
2 b c cos(θ) = b² + a² - c²
cos(θ) = (b² + a² - c²) / 2 b c
θ = cos⁻¹( (b² + a² - c²) / (2 b c) )
θ = cos⁻¹( (8² + 12² - 16²) / 2(8)(16) )
<em>θ = 100.8°</em>
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Therefore, the angle between their paths is <em>100.8°</em>
Answer:
Step-by-step explanation:
50 dollars = ∉34
∉1 = Rs 150
Rs 382800 / 150 Rs per ∉ = 382800/150 ∉
=2552 ∉
50 dollars = ∉34 so 50/34 dollars = ∉
2552 ∉ × 50/34 dollar per ∉ = in the units the ∉ cancel out
∉ × dollar/∉ = dollars
(2552 × 50) / 34 = 3752.94 dollars <------------------
Here is another way of looking at the answer...........
Rs 382800 × 1∉/150 Rs × 50 dollars/34 ∉ = note how the units cancel
= 382800 × (1/150) × (50/34) Rs × ∉/Rs × dollars/∉
= 3,752.94 dollars leaving only dollars in the numerator
Answer:
It C
Step-by-step explanation:
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
