we know that
p^2 is the the frequency of hba homozygote
we are given
frequency of hba homozygotes is 0.1
so,
p^2 =frequency of hba homozygotes
we can plug values
and we get
..............Answer
Answer:
One rose bush = $3
One bunch of ornamental grass = $4
Step-by-step explanation:
We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

Thus, 1 bunch of ornamental grass is $4.
Answer:200 minutes
Step-by-step explanation:
1 minute = 60 seconds.
6/3 = 2 (20 seconds) 1 photo every 20 seconds.
600x20 = 12000. seconds.
12000/60 = 200 (200 minutes)
Set it up with variables; tomatoes=t, sunflowers=s, corn=c
320=t+s+c
This year;
t=2s
c=t+40
so, replace 2s for t; c=2s+40
now we can put those factors in for 320=t+c+s
320= 2s+2s+40+s
(SIMPLIFY)---> 320=5s+40----> 5s+280----> s=56
now incorporate the s value into the other equations.
c=2s+40----> c=56(2)=40 ----> c=152
t=2s -----> t=2(56) ----> t=112
TOMATOES= 112 acres
CORN= 152 acres
SUNFLOWERS= 56 acres
To check your work: 320=t+s+c ----> 320=112+156+56
5:4 = 10:8 = length:width
10+8=18
162÷18= 9
9×10= 90
the length of the rectangle is D. 90 ft