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katen-ka-za [31]
3 years ago
5

A bag contains 25 cents and 50 cent coins whose total value is $30 if the number of 25 cent coins is four times that of 50 cent

coins, find the number of each type coins. please may I also have the equation.​
Mathematics
2 answers:
damaskus [11]3 years ago
4 0

Number of 25 cents coins is  80 and number of 50 cents coins is 20.

Step-by-step explanation:

Given,

A bag contains of total value $ 30.

Number of 25 cent coins is four times that of 50 cent coins.

To find number of 25 cents coin is x

Number of 50 cents coin is y

According to the problem,

\frac{x}{4} +\frac{y}{2} = 30 ----- eq 1

x = 4y------ eq 2

Now, we will solve these two equation.

Putting the values of x = 4y in eq 1 we get,

\frac{4y}{4} +\frac{y}{2} = 30

or,  y +\frac{y}{2} = 30

or, \frac{3y}{2} = 30

or, y = 20

So, x = 4×20 = 80

Hence,

Number of 25 cents coins = 80 and number of 50 cents coins = 20

polet [3.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

Let 25 cent coin be A and 50 cent coin be B

Given

Total value of 25 cents coin and 50cents coin is $30

That’s

25A + 50B = 30

Also, 25 cents coin is equal to four times that of 50

So,

A = 4B

We now have

25A + 50B = 30

A = 4B

Substitute 4B for A into the first equation

25(4B) + 50B = 30

25 x 4B + 50B = 30

100B + 50B = 30

150B = 30

Divide both sides by 150 to isolate B

150B/150 = 30/150

B = 1/5

Recall

A = 4B

Therefore

A = 4 x 1/5

= 4/5

Number of 25 cents coin is 4/5 and that of 50 cents coin is 1/5

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