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2 years ago

Consider the following equation. 6 ^ ( -x ) + 4 = 3x -1

Mathematics

2 answers:

maw [93]2 years ago

6 0

Answer:

1.68

Step-by-step explanation:

1. Move all of the terms to the left side and set the problem equal to zero.

2. Set each factor equal to zero.

Molodets [167]2 years ago

5 0

For this case we have the following equation:

$6 ^ {- x} + 4 = 3x-1$

We must clear the value of x, we follow the steps below:

We subtract 3x on both sides of the equation: $6 ^ {- x} -3x + 4 = -1$

Add 1 to both sides of the equation:

$6 ^ {- x} - 3x + 4 + 1 = -1 + 1\\6 ^ {- x} - 3x + 5 = 0$

Each side of the equation is drawn, then the solution is the x value of the intersection point.

$x = 1.68$

Answer:

See attached image

$x = 1.68$

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3 years ago

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2 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

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goldenfox [79]

Answer:

Step-by-step explanation:

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nirvana33 [79]

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2 years ago

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