To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.
Answer:
5x - 2y = -2
Step-by-step explanation:
-2x - (-7x) = -2x + 7x = 5x
y - 3y = -2y
0 - 2 = -2
There is actually 2 ways to solve this, I will show you both.
The first is obvious, solve for x in the first one, and plug it into the 2nd one and get the answer
4x + 7 = 12
4x = 5
x = 
8() + 3
2 * 5 + 3
10 + 3
13
The 2nd option is to manipulate the 4x + 7 to be 8x + 3
4x + 7 = 12
start by moving the 7 over
4x = 5
multiply both sides by 2
8x = 10
and add 3 to both sides
8x + 3 = 13
Answer:
0
Step-by-step explanation:
Assuming the problem is:
"lim x-> 4 f(x)=5 lim x-> 4 g(x)=0 and lim x-> 4 h(x)=-2, then find lim x->4 (fg)(x)"
lim x->4 (fg)(x)
Since we know the limits of f and g at x=4 exist we can write the limit as:
lim x->4 f(x) lim x->4 g(x) (since fg(x) means f times g of x.)
5(0)
0
There are 4 multiples of 5 between 1-20 5.10.15.20 which are 4/20 aka 1/5 so 1/5 of 200 is 20 times Yaga yeet
