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Natasha2012 [34]
3 years ago
14

Of the runners in a marathon through Northeastern Pennsylvania, 94.12% finished the race. If 2,125 runners started the race, how

many finished the race?
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0
2125 started.....94.12% finished

94.12% of 2125 = 
0.9412(2125) = 2000.05 finished


Burka [1]3 years ago
6 0
To determine the number of persons (racers) who finished the race, we just have to multiply the number of runners at the start, 2125, by the decimal equivalent of the given percentage, 0.9412. That is,
                          n = 2125 x 0.9412 = 2000
Therefore, 2000 finished the race. 
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Answer:

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2 years ago
: Which equations have an infinite number of solutions? Select all that apply. A -2(x - 2) + 3x = x - 4 B 2x + 4(x - 1) = 3(2x +
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Option C and Option D

3x + 2(x - 2) + 6 = 2(2x + 3) + x - 4 has infinite number of solutions

4(x + 2) + x + 1 = 2x - 3 + 3(x + 4) has infinite number of solutions

<h3><u>Solution:</u></h3>

Given that we have to find the equations that has infinite number of solutions

If we end up with the same term on both sides of the equal sign, such as 4 = 4 or 4x = 4x, then we have infinite solutions.

If we end up with different numbers on either side of the equal sign, as in 4 = 5, then we have no solutions.

<h3><u>Option A</u></h3>

-2(x - 2) + 3x = x - 4

Multiply the terms inside the bracket

-2x + 4 + 3x = x - 4

x + 4 = x - 4

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<h3><u>Option B</u></h3>

2x + 4(x - 1) = 3(2x + 1) - 2(x - 1)

2x + 4x - 4 = 6x + 3 - 2x + 2

6x - 4 = 4x + 5

6x - 4x = 5 + 4

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x = \frac{9}{2}

Thus this equation has only one solution.

Thus this equation does not have infinite number of solutions

<h3><u>Option C</u></h3>

3x + 2(x - 2) + 6 = 2(2x + 3) + x - 4

3x + 2x - 4 + 6 = 4x + 6 + x - 4

5x + 2 = 5x + 2

Thus this equation has infinite number of solutions

<h3><u>Option D</u></h3>

4(x + 2) + x + 1 = 2x - 3 + 3(x + 4)

4x + 8 + x + 1 = 2x - 3 + 3x + 12

5x + 9 = 5x + 9

Thus this equation has infinite number of solutions

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The answer I believe is:
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Hope I could help! Have a good one.
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