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NeX [460]
3 years ago
9

What is the result of subtracting the second equation from the first?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

5x - 2y = -2

Step-by-step explanation:

-2x - (-7x) = -2x + 7x = 5x

y - 3y = -2y

0 - 2 = -2

salantis [7]3 years ago
3 0

Answer:

5x  -2y = -2

Step-by-step explanation:

-2x + y = 0

-7x + 3y = 2

Subtract the second equation from the first

-2x + y = 0

-(-7x + 3y = 2)

--------------------------

Distribute the minus sign

-2x + y = 0

+7x - 3y = -2

--------------------------

5x  -2y = -2

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Answer:

10.23 miles

Step-by-step explanation:

1 hour = 3600 seconds

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Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0
Sonja [21]

Answer:

\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}

Step-by-step explanation:

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8 0
3 years ago
3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili
choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

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