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Tamiku [17]
3 years ago
5

James works in a flower shop. he will put 36 flowers in vases for a wedding. he must put the same amount of tulips in each vase.

the number of tulips in a vase must be greater than 1 and less than 10. how many tulips could be in each vase.
Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0
- If he has 18 vases, he can put 2 tulips in each
- If he has 12 vases, he can put 3 tulips in each 
- If he has 9 vases, he can put 4 tulips in each
- If he has 6 vases, he can put 6 tulips in each 
- If he has 4 vases, he can put 9 tulips in each 
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olganol [36]

Answer:X is any number more than 7

Source:trust me bro

4 0
3 years ago
Read 2 more answers
Can anybody teach me how to solve this pls​
wel
Answer is 10 and 170, complementary angles are 90°, while supplementary angles are 180 in total, if angle A is 80 then you subtract 90 by 80 and you get 10, so that is angle B, So then you are asked what is angle C. Which is part of the supplementary angle so you take the 10° that you got from B and then you subtract 180 by the 10, And thats how you get 170 and that's how you know that C is 170 (hope this explanation helps)
3 0
2 years ago
What is the domain of the function y= square root of X plus 4​
kumpel [21]

Answer: all real numbers

Step-by-step explanation:

the domain for any function is always, all real numbers or in other words, negative infinity to positive infinity.

5 0
3 years ago
50+ POINTS I NEED HELP
olga nikolaevna [1]

Answer:

<u><em>21 yard line</em></u>

Step-by-step explanation:

Ok we start out on the 20 yard line, we need to add the yards together.

<em>We add the 6 to the 20:</em>

20+6=26

<em>Then we subtract the 8 yards from our new 26:</em>

26-8=18

<em>Then we add the 18 by 3:</em>

18+3=21

Therefore,

<em>The Answer is 21 Yard Line.</em>

Hope I could help, If you need some more assistance ask me!

8 0
3 years ago
Find dy/dx by implicit differentiation. <br> 4x2 + 5xy - y2 = 6
Vlada [557]
4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0

where y' = dy/dx

8x + 5xy' +5y  -2yy' = 0

combining y' terms
y' (5x-2y) +8x +5y = 0

y'(5x-2y) = -(8x+5y)

dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)
5 0
3 years ago
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