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quester [9]
3 years ago
6

1.Morgan drives 24 miles due north, then drives 7 miles due east from home to work. What is the distance between Morgan’s home a

nd work, measured in a straight line?
2. Hailey is flying a kite on a string 25m long. The kite is directly above Cassi who is 15m from Hailey. How high is the kite above the ground?

Use the Pythagorean theorem to solve each problem. Show Calculations.
Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

1) 25 miles

2) 20 m

Step-by-step explanation:

Number 1 is going to be

a^{2} + b^{2}  = c^{2} because it's a right triangle

So

24^{2} + 7^{2} = c^{2}

625 = c^{2}

c = 25 mile

Number 2 uses the same process, but changing to using C instead of A

a^2 = c^2 - b^2

a^2 = 625 - 225

a = \sqrt(400)

a = 20m

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3 years ago
Can u please help me with this 2 problem please
Mice21 [21]
<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
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<h3>Find</h3>
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The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

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