Answer:
- The lowest value of the confidence interval is 0.5262 or 52.62%
- The highest value of the confidence interval is 0.5538 or 55.38%
Step-by-step explanation:
Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.
The general expression to apply here is;

where ;
p=sample proportion
n=sample size
z*=value of z* from the standard normal distribution for 95% confidence level
Given;
n=5000
<u>Find p</u>
From the question 54% of people chosen said they did not have children under 18 living at home

<u>To calculate the 95% confidence interval, follow the steps below;</u>
- Find the value of z* from the z*-value table
The value of z* from the table is 1.96
- calculate the sample proportion p
The value of p=0.54 as calculated above

Divide the value of p(1-p) with the sample size, n

- Find the square-root of p(1-p)/n

Here multiply the square-root of p(1-p)/n by the z*

The 95% confidence interval for the lower end value is p-margin of error

The 95% confidence interval for the upper end value is p+margin of error

pls double check these im not super sure
im p sure the first one with || means parallel n second one means perpendicular lol
Answer:
m= ll m= -1/3
m= ⊥ m= 3
Step-by-step explanation:
uh regular slope
m = -1/3
parallel - slope is same
perpendicular - product of slopes is -1
Answer:
(-1,-2)
Step-by-step explanation:
Answer:
The probability that the page will get at least one hit during any given minute is 0.9093.
Step-by-step explanation:
Let <em>X</em> = number of hits a web page receives per minute.
The random variable <em>X</em> follows a Poisson distribution with parameter,
<em>λ</em> = 2.4.
The probability function of a Poisson distribution is:

Compute the probability that the page will get at least one hit during any given minute as follows:
P (X ≥ 1) = 1 - P (X < 1)
= 1 - P (X = 0)

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.