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Eva8 [605]
3 years ago
13

Based on the concept of phylogeny, an organism that was ancestral to both the bacteria and eukaryota domains would exhibit which

of the following characteristics?
A. It would have a nucleus.
B. It would have cell walls as well as cell membranes.
C. It would have DNA.
D. It would have mitochondria and other membrane-bound organelles.
Biology
2 answers:
Helen [10]3 years ago
5 0
"It would have DNA." is the one among the following characteristics that would be exhibited based <span>on the concept of phylogeny, an organism that was ancestral to both the bacteria and eukaryota domains. The correct option among all the options that are given in the question is the third option or option "C". </span>
777dan777 [17]3 years ago
5 0

Answer: The correct answer is-

C. It would have DNA.

DNA is considered as the genetic material of life forms that carries genetic information in the form of nucleotide sequences. The genetic information is passed from one generation to the next generation.

Phylogeny can be described as the study of evolutionary history ( that is how different organism evolve from their ancestors) of different life forms and represents relationships among various species.

As we know that DNA is the genetic material that is transferred from one generation to the next generation, therefore  an organism that was ancestral to both the bacteria and eukaryota domains would also have the genetic material that is DNA.

Thus, option C) is the right answer.

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7 0
3 years ago
What is the probability that the first offspring from the cross listed below will be heterozygous for all loci?
Tanya [424]

Answer and Explanation:

<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee

We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:

1) aa     x     AA

F1) 4/4=1 Aa

2) Bb    x    bb

F1) ½ bb

     ½ Bb

3) dd    x    Dd

F1) ½ dd

     ½ Dd

4) Ee    x    Ee

F1) ¼ EE

    2/4 = ½ Ee

     ¼ ee

So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:  

1 Aa   x   ½ Bb   x    ½ Dd    x    ½ Ee = 1/8 AaBbDdEe

                                 

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Help plz:
otez555 [7]

Answer:

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Answer:

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