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Zina [86]
3 years ago
15

An engineer is designing a small toy car that a spring will launch from rest along a racetrack. She wants to maximize the kineti

c energy of the toy car when it launches from the end of a compressed spring onto the track, but she can make only a slight adjustment to the initial conditions of the car. The speed of the car just as it moves away from the spring onto the track is called the launch speed. Which of the following modifications to the car design would have the greatest effect on increasing the kinetic energy of the car? Explain your reasoning.
Decrease the mass of the car slightly.
Increase the mass of the car slightly.
Decrease the launch speed of the car slightly.
Increase the launch speed of the car slightly.
Physics
1 answer:
balandron [24]3 years ago
7 0

Answer:

we see that to increase the energy of the expensive we must increase the launch speed, since it increases quadratically

Explanation:

Kinetic energy is

            K = ½ m v²

the speed of the expensive we can find it r

            v² = v₀² + 2 a x

we can find acceleration with Newton's second law

            F = m a

             a = F / m

             F= cte

substitute in the velocity equation

           v² = v₀² + 2 F/m  x

let's substitute in the kinetic energize equation

         K = ½ m (v₀² + 2 F/m  x)

           

         K = ½ m v₀²  + f x

we see that the kinetic energy depends on two tomines

in January in these systems the force for launching is constant, which is why decreasing the mass increases the speed of the vehicle and therefore increases the kinetic energy

As the launch speed increases the initial energy increases quadratically

we see that to increase the energy of the expensive we must increase the launch speed, since it increases quadratically

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Responder:

Compruebe amablemente la explicación

Explicación:

¿Qué significa que un automóvil viaje con una rapidez de 45 [(Km.) ⁄ (Hr.)]?

Si se dice que un automóvil viaja a una velocidad de 45 km / h, entonces el automóvil cubre una distancia de 45 km en una hora. 45 km / h es una derivación de la velocidad de desplazamiento obtenida de la relación;

Velocidad = distancia / tiempo

Velocidad = 45 km / 1 h.

Distancia = velocidad × tiempo

Distancia = 45 km / h × 1 h

Distancia = 45 km

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3 years ago
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To drive to the store from home, somebody first travels 5 km west, then they travel 5 km northwest. What is the straight line di
schepotkina [342]
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A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is
nadezda [96]

Answer:

in the downward movement of the movement when the constant is lost

Explanation:

When the coin is on the piston it has a relationship given by

       a = d²x / dt²

the piston position is

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the maximum acceleration is

     a = - A w²

When the piston raises the acceleration of gravity and that of the piston go in the same direction, when the piston descends they relate it is contrary to gravity, therefore when the frequency increases, the point where the acceleration of the piston is greater than gravity arrives and the coin loses contact.

The point where you lose contact is

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In short, in the downward movement of the movement when the constant is lost

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Answer:

kg m/s

Explanation:

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The unit of MeV/c in SI fundamental units is kg m/s

5 0
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