Answer:
we see that to increase the energy of the expensive we must increase the launch speed, since it increases quadratically
Explanation:
Kinetic energy is
K = ½ m v²
the speed of the expensive we can find it r
v² = v₀² + 2 a x
we can find acceleration with Newton's second law
F = m a
a = F / m
F= cte
substitute in the velocity equation
v² = v₀² + 2 F/m x
let's substitute in the kinetic energize equation
K = ½ m (v₀² + 2 F/m x)
K = ½ m v₀² + f x
we see that the kinetic energy depends on two tomines
in January in these systems the force for launching is constant, which is why decreasing the mass increases the speed of the vehicle and therefore increases the kinetic energy
As the launch speed increases the initial energy increases quadratically
we see that to increase the energy of the expensive we must increase the launch speed, since it increases quadratically
