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2 years ago

b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?

Physics

1 answer:

umka2103 [35]2 years ago

6 0

Answer:

Twice.

Explanation:

The momentum of an object is given by :

p = mv

Where

m is mass and v is the velocity

If the mass of the ball were doubled, m'=2m and v'=v=3 m/s

New momentum,

p'=m'v'

p'=2m × v

p'=2mv

p'=2p

So, the new momentum becomes twice the initial momentum.

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3 years ago

If the back of the truck is 1.3 m above the ground and the ramp is inclined at 22 ∘ , how much time do the workers have to get t

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Refer to the diagram shown below.

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3 years ago

Suppose that a balloon is being filled with air at a rate of 10 cm3/s. (Assume that theballoon is a perfect sphere.) At what rat

Basile [38]

Answer:

Therefore the surface area of the balloon is increased at 4 cm³/s.

Explanation:

The balloon is being filled with air at a rate of 10 cm³/s

It means the volume of the balloon is increased at a rate 10 cm³/s.

i.e $\frac{dv}{dt} =10 cm^3/s$

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$S=4\pi r^2$

Differentiate with respect to t

$\frac{dS}{dt} =4\pi\times2r\frac{dr}{dt}$

$\Rightarrow \frac{dS}{dt} =8\pi r\frac{dr}{dt}$

Putting the value of $\frac{dr}{dt}$

$\Rightarrow \frac{dS}{dt} =8\pi r\times\frac{10}{4\pi r^2}$

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3 years ago

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Answer:

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3 years ago

b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?​

b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?