Answer:

Explanation:
The final angle speed of the merry-go-round is determined with the help of the Principle of Angular Momentum Conservation:
![(270\,kg\cdot m^{2})\cdot \left(8\,rpm\right) = [270\,kg\cdot m^{2}+(27\,kg)\cdot (1.80\,m)^{2}]\cdot \dot n](https://tex.z-dn.net/?f=%28270%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%29%5Ccdot%20%5Cleft%288%5C%2Crpm%5Cright%29%20%3D%20%5B270%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%2B%2827%5C%2Ckg%29%5Ccdot%20%281.80%5C%2Cm%29%5E%7B2%7D%5D%5Ccdot%20%5Cdot%20n)

Answer:
g = 11.2 m/s²
Explanation:
First, we will calculate the time period of the pendulum:

where,
T = Time period = ?
t = time taken = 135 s
n = no. of swings in given time = 98
Therefore,

T = 1.38 s
Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

where,
l = length of pendulum = 54 cm = 0.54 m
g = acceleration due to gravity on the planet = ?
Therefore,

<u>g = 11.2 m/s²</u>
Answer:
There is a right angle and it has three sides.
Explanation:
There are two 45 degree angles and since a triangles sides ALWAYS add up to 180 we know the the other side has to be 90 degrees because 45+45+90=180. And we know that every triangle has three sides because "tri" means three.
Explanation: Solution
1.
Gravitational potential energy
U=mgh=500*9.8*50
U=245000 J
2.
Kinetic energy is present at bottom of the hill
K=(1/2)mV2=(1/2)*500*27.82
K=193210 J
3.
Work done by friction
W=193210-245000=-51790 J
Answer:
Even though the sun is 330,000 times more massive than earth, the distance makes it so its gravitational pull on us is negligeable compared to the earth's.