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kondaur [170]
3 years ago
15

Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30 kg box at the same

acceleration, how much force will Brianna need to apply?
Physics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

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A playground merry-go-round of radius R = 1.80 m has a moment of inertia I = 270 kg · m2 and is rotating at 8.0 rev/min about a
Arte-miy333 [17]

Answer:

\dot n = 6.042\,rpm

Explanation:

The final angle speed of the merry-go-round is determined with the help of the Principle of Angular Momentum Conservation:

(270\,kg\cdot m^{2})\cdot \left(8\,rpm\right) = [270\,kg\cdot m^{2}+(27\,kg)\cdot (1.80\,m)^{2}]\cdot \dot n

\dot n = 6.042\,rpm

3 0
3 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that
Natasha2012 [34]

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

T = \frac{t}{n}

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

T = \frac{135\ s}{98}

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

T = 2\pi \sqrt{\frac{l}{g}}

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}

<u>g = 11.2 m/s²</u>

3 0
3 years ago
This triangle is an isosceles right triangle. This means that the triangle contains a _____ angle and _______ sides.
Svetlanka [38]

Answer:

There is a right angle and it has three sides.

Explanation:

There are two 45 degree angles and since a triangles sides ALWAYS add up to 180 we know the the other side has to be 90 degrees because 45+45+90=180. And we know that every triangle has three sides because "tri" means three.

3 0
2 years ago
Read 2 more answers
A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
rjkz [21]

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

3 0
3 years ago
Why we feel the earth's gravity better than the suns
VashaNatasha [74]

Answer:

Even though the sun is 330,000 times more massive than earth, the distance makes it so its gravitational pull on us is negligeable compared to the earth's.

7 0
3 years ago
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