All categories

3 years ago

0.6y + 0.8 = 0.28y + 1.12 Pls help

Mathematics

2 answers:

bogdanovich [222]3 years ago

3 0

Answer:

y = 1

Step-by-step explanation:

Given

0.6y + 0.8 = 0.28y + 1.12 ( subtract 0.28y from both sides )

0.32y + 0.8 = 1.12 ( subtract 0.8 from both sides )

0.32y = 0.32 ( divide both sides by 0.32 )

y = 1

torisob [31]3 years ago

3 0

Answer:

0.5594 or 1

Step-by-step explanation:

0.6y+0.8=0.28y+1.12

collect like terms

0.6y-0.28y=1.12-0.8

0.572y=0.32

0.572y\0.572=0.32\0.572

y=0.5594

Approximately

y=1

You might be interested in

How to find the area and what’s the correct answer

kirill [66]

What you're seeing here is a rectangle attached to a semi-circle.

To find the area of a rectangle, multiply the length times the width. (lw)

To find the area of a semi-circle, use this formula:

$\frac{1}{2} \pi \times {r}^{2}$

To find your answer, first get the two dimensions of the rectangle

$l = 7 \: w \:= 3$

and multiply.

$lw = 21$

Now look at the semi-circle. We can see that it has a diameter of 3. Since the radius is equal to half, 1/2 the diameter, our radius is then 1.5.

$\frac{1}{2} \times \pi \times {1.5}^{2}$

We can also calculate this manually:

$0.5 \times 3.14 \times 1.5 \times 1.5$

Add the dimensions of both objects together now.

$21 + 3.5325 = 24.5325 \: cm {}^{2}$

Your geometric figure has a total area of 24.5325 cm.

3 0

4 years ago

Solve the equation 2w=58

Free_Kalibri [48]

W = 29
Divided both sides by 2

7 0

3 years ago

Read 2 more answers

A recent study in a small city stated that the average age of robbery victims was 63.5 years. A random sample of 20 recent victi

Elina [12.6K]

Answer:

The p-value of the test is of 0.3219 > 0.05, which means that at $\alpha = 0.05$ , the average age is not higher than originally believed.

Step-by-step explanation:

A recent study in a small city stated that the average age of robbery victims was 63.5 years. Test if the average age higher than originally believed.

At the null hypothesis, we test that the mean is the believed mean age of 63.5 years, that is:

$H_0: \mu = 63.5$

At the alternate hypothesis, we test if this mean is higher, that is:

$H_1: \mu > 63.5$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

63.5 is tested at the null hypothesis:

This means that $\mu = 63.5$

A random sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years.

This means that $n = 20, X = 63.7, s = 1.9$

Test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{63.7 - 63.5}{\frac{1.9}{\sqrt{20}}}$

$t = 0.47$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 63.7, which is a right-tailed test, with t = 0.47 and 20 - 1 = 19 degrees of freedom.

With the help of a calculator, this probability is of 0.3219.

The p-value of the test is of 0.3219 > 0.05, which means that at $\alpha = 0.05$ , the average age is not higher than originally believed.

5 0

3 years ago

Of the bundles delivered daily to the store, 1/3

Triss [41]

Answer:

x=9

Step-by-step explanation:

Let total bundle=x

Morning edition of the daily sun=1/3x

=x/3

Afternoon edition of the daily sun=2

That leaves 2x/3 - 2, of which

x/3 - 1 are regional

1 is local

1 from another state

Sum everything

x = x/3 + 2 + x/3 - 1 + 1 + 1

x=2x/3 +3

x-2x/3=3

3x-2x/3=3

x/3=3

Cross product

x=3×3

x = 9

3 0

4 years ago

Please I need help I will mark brainiest

kenny6666 [7]

Answer:

sorry i looked and i tried, but i dont know the answer.

Step-by-step explanation:

6 0

3 years ago