Answer:
B. 36 square units
Step-by-step explanation:
This is a triangle and to calculate the area of a triangle we multiply height with base and that divided by two
The height of this triangle is 8 units and the base is 9 units
9 × 8 ÷ 2 = 36 square units
First, let's calculate the mean and the mean absolute deviation of the first bowler.
FIRST BOWLER: <span>8,5,5,6,8,7,4,7,6
Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9
<em>Mean = 6.222</em>
Mean absolute deviation or MAD = [</span>∑(|Data Point - Mean|]/Number of Data Points
MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9
<em>MAD = 1.136</em>
SECOND BOWLER: <span>10,6,8,8,5,5,6,8,9
</span>Mean = (Sum of all data)/(Number of data points) = (<span>10+6+8+8+5+5+6+8+9</span>)/9
<em>Mean = 7.222</em>
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9
<em>MAD = 1.531
</em>
The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. <em>B</em><em>etween the two, the first bowler is more consistent.</em>
Answer: option c
Step-by-step explanation:
To solve this problem you must keep on mind the properties of logarithms:

Therefore, knowing the properties, you can write the expression gven in the problem as shown below:
Answer:
x = -8
Step-by-step explanation:
1/4x+2=-5/8x-5
Add 5/8 x to each side
1/4x + 5/8 x+2=-5/8x + 5/8x-5
1/4x + 5/8x +2 = -5
Subtract 2 from each side
1/4x + 5/8x +2-2 = -5-2
1/4x + 5/8x = -7
Get a common denominator of 8
1/4 *2/2 x + 5/8x = -7
2/8x + 5/8x = -7
7/8x = -7
Multiply each side by 8/7
8/7 * 7/8x = -7*8/7
x = -8
Answer:
I think it's -6x-18, this queston uses distributive property, so you must multiply each term inside the parenthesis to the number outside the parenthesis.