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3 years ago

5

Suppose you got 8 mangoes and 3 apples for $18 and 3 mangoes and 5 apples for $14.50.

1 answer:

Mandarinka [93]3 years ago

7 0

Let x = cost of mango
y = c of apples
<span>8x+3y=18.
3x+5y=14.5 </span>

<span> </span>
<span>24x+9y=54
24x+40y=116
multiplying them with 3 and 8 resectively. </span>
<span>subtract one from the other we get </span>
<span>40y-9y=116-54 </span>
<span>31y=62 </span>
<span>y=2.
cost of apple=2$ per apple
</span><span>8x+3y=18,
8x+3(2)=18.
8x=12. x=12/8=1.5 </span>
<span>cost of mango i= 1.5 $ per mango
hope this helps</span>

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