Given that 1 pint is equal to 437 ml
and 1000 ml=1 liter
then
1 pint =(437/1000) liters
simplifying we get:
1 pint= 0.437 liters
thus amount of pints in 4 liters will be:
4/0.473
=8.45666586
~8.5 pints
Answer:
A)Option D
B)P(X = 15) = 0.1325
Step-by-step explanation:
A) From the question, the information given follows binomial distribution because there are two mutually exclusive outcomes for each trial, there is a fixed number of trials. The outcome of one trial does not affect the outcome of another, and the probability of success is the same for each trial.
So option D is correct.
B) From the question, we are told that the poll reported that 66 percent of adults were satisfied with the job. Thus, probability is; p = 0.66
Let X be the number of adults satisfied with the job. Since 25 are selected,
Thus;
P(X = 15) = C(25, 15) * (0.66)^(15) * (1 - 0.66)^(25 - 15)
P(X = 15) = 3268760 × 0.00196407937 × 0.00002064378
P(X = 15) = 0.1325
I would help but i don’t see a figure
The given equation, x.cosec²x = cot x - d/dx x.cot x, is proved using the product rule of differentials.
In the question, we are asked to show that x.cosec²x = cot x - d/dx x.cot x.
To prove, we go by the right-hand side of the equation:
cot x - d/dx x.cot x.
We solve the differential d/dx using the product rule, according to which, d/dx uv = u. d/dx(v) + v. d/dx(u), where u and v are functions of x.
cot x - {x. d/dx(cot x) + cot x. d/dx(x)}
= cot x - {x. (-cosec²x) + cot x} {Since, d/dx(cot x) = -cosec²x, and d/dx(x) = 1}
= cot x + x. cosec²x - cot x
= x. cosec²x
= The left-hand side of the equation.
Thus, the given equation, x.cosec²x = cot x - d/dx x.cot x, is proved using the product rule of differentials.
Learn more about differentials at
brainly.com/question/14830750
#SPJ1
Answer:
The second difference, let suppose denoted by d₂, can be obtained by taking the difference between consecutive terms of the first difference of y-values, such as:
Step-by-step explanation:
Given the table
x y
0 3
1 4
2 7
3 12
The (first) difference, let suppose denoted by d, of y values can be obtained by taking the difference between consecutive terms.
The second difference, let suppose denoted by d₂, can be obtained by taking the difference between consecutive terms of the first difference of y-values, such as:
