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blondinia [14]
2 years ago
11

The choices are X < -6 X > -6 X<_ -6 X> -6

Mathematics
2 answers:
slamgirl [31]2 years ago
6 0

<u>Answer</u>:

x < = -6

<u>Explanation</u>:

The arrow points -6 and then to the left side, where lies negative numbers, all along. The dot is filled and points that x is also equal to -6 and less than that of -6. Therefore the inequality is:

  • x < = -6

  • {Interval\:Notation:}&\:\left(-\infty \:,\:-6\right)\end{bmatrix}
elena-14-01-66 [18.8K]2 years ago
5 0
  • Starting point of arrow is -6.
  • The arrow is travelling to wards left.
  • I.e the arrow is decreasing and x is decreasing.

Hence the solution is

\\ \tt\hookrightarrow x\in (-\infty,-6]

  • x<=-6
You might be interested in
Click the square near each correct choice to fill it in. Be sure to mark all correct answers.
Bumek [7]

Answer:

The correct options are;

A. 1·2 = 2

B. 1·1 = 1

E. 1 + 1 = 2

Step-by-step explanation:

Given that the equations 1.2 = 2 and 1.1 = 1 are correctly written as 1·2 = 2 and 1·1 = 2, we have;

The product of any number and one is equal the same number, that is a × 1 = a

Whereby we have the expression 1·2 which is 1 × 2,  we therefore have;

1 × 2 = 1 · 2= 2

B. Similarly we have;

1 · 1 = 1 × 1 = 1

Also, 1 + 1 = 2 is correct as the sum of two numbers is equal to the sum of the count of the numbers, therefore;

E. 1 + 1 = 2 is correct.

3 0
3 years ago
How do you solve x^4 - 3x^3 - 3x^2 - 75x - 700
madam [21]

Answer:

  = (x +4)(x -7)(x^2 +25)

  roots are -4, 7, ±5i

Step-by-step explanation:

You have not said what "solve" means in this context. An expression by itself doesn't have a solution. We have assumed you want to find the factoring and/or roots of it.

I like to use a graphing calculator to find the real roots. For this expression, there are two of them, one positive and one negative. (You know there will be one positive real root, and at least one negative real root, from Descartes's rule of signs.)

Then those roots can be factored out and the solution to the remaining quadratic determined. That factoring can occur by polynomial long division, synthetic division, or other means.

I like to see what happens when I plot the graph of the function divided by the known factors. (We expect a parabola that doesn't cross the x-axis.) The vertex of that parabola can be used to find the remaining roots.

The x-intercepts of the given expression are -4 and +7, so two of the factors are (x+4) and (x-7). Dividing these from the given expression (by synthetic division or other means) gives (x^2 +25). This only has imaginary roots (±5i).

____

If you're constrained to doing this "by hand" with only a scientific calculator, Descartes's rule of signs tells you there is one positive real root. (Only one sign change in the sequence of coefficient signs: +----.)

The rational root theorem tells you it will be a divisor of 700. Various estimates of the maximum magnitude of it will tell you it is probably less than 14 (easily checked). So, the numbers you can test as roots would be 1, 2, 4, 5, 7, 10, 14. You will find that 7 is a root, and then you can reduce the problem to the cubic x^3 +4x^2 +25x +100.

When odd-degree term signs are changed, there will be 3 sign changes (-+-+), hence at least one negative real root. The rational root theorem tells you it is a divisor of 100, so possible choices are -1, -2, -4, -5. By trial and error or other means, you can find the root to be -4. Then the problem reduces to the quadratic x^2 +25.

Roots of that are ±√(-25) = ±5i.

This process generally entails a fair amount of trial-and-error work, which is why I prefer one that makes some use of technology.

_____

We have presumed you have some familiarity with ...

  • Descartes's rule of signs
  • Rational Root Theorem
  • synthetic division

This will usually be the case when you're presented with problems like this. If you need additional information on any of these, it is readily available on the internet (and probably also in your reference material).

4 0
3 years ago
HhH. The length of a rectangle is 5 ft more than the width.
Vaselesa [24]

Answer:

Easy, it's A.

5 more can be written as 5+ or +5. W is the width, so 5 more than the width is written as 5+w

5 0
3 years ago
What is the constant of variation for the quadratic variation? x 2 3 4 5 6 y 32 72 128 200 288
cluponka [151]
We use different models for different types of variation. For example, linear variation is associated with the formula y=ax, or the more familiar y=mx+b (the equation of a straight line). Cubic variation: y=a*x^3. In the present case we're discussing quadratic variation; perhaps that will ring a bell with you, reminding you that y=ax^2+bx+c is the general quadratic function. Now in y our math problem, we're told that this is a case of quadratic variation. Use the model y=a*x^2. For example, we know that if x=2, y =32. Mind substituting those two values into y=a*x^2 and solving for y? Then you could re-write y=a*x^2 substituting this value for a. Then check thisd value by substituting x=3, y=72, and see whether the resulting equation is true or not. If it is, your a value is correct. But overall I got 16!
7 0
3 years ago
Kelly was baking bread but could only find her 1/8 cup measuring cup. She needs 1/4 cup sugar,3/4 cup whole wheat flour, and 1/2
irga5000 [103]

Answer:

Step-by-step explanation:

cups

for sugar=1/4÷1/8=1/4×8=2

whole wheat flour=3/4÷1/8=3/4×8=6

all purpose flour=1/2÷1/8=1/2×8=4

6 0
3 years ago
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