Answer:
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Step-by-step explanation:
Answer:
The profit will be maximum on x = 250.
Step-by-step explanation:
From the given information:
Revenue = 1500x - x²
Cost = 1500 + 1000x
As we know that
Profit = Revenue - Cost ; Let say it equation 1
Then after putting the values of revenue and cost in equation 1 we have:
Profit = (1500x - x²) - (1500 + 1000x)
Profit = 1500x - x² - 1500 - 1000x
Profit = -x² + 500x - 1500
We know that at the max or min the slope of the graph formed by the profit function will be zero, therefore we find the slope of profit function by taking the first derrivative w.r.t. x as under:
d(Profit)/dx = d/dx(-x² + 500x - 1500)
d(Profit)/dx = -2x + 500
By putting the above slope equal to zero we get:
d(Profit)/dx = -2x + 500 = 0
-2x + 500 = 0
-2x = -500
x = 250
Therefore it is concluded that the profit will be maximum when x will be equal to 250.
You have to subtract 23.75 from 42.50 to get your answer of 18.75
D = 1/2 a t^2 is given. And it wants you to find t in terms if a and d. Which means, you need to arrange the equation and let t be alone.
If you let t^2 alone ;
2d/a = t^2
And square root t^2 will give you t ;
SquareRoot(2d/a) = t
The answer is (2)
Answer:
I believe the question says "5j + 16 - 12(-9j - 4) - 12j" I hope I'm correct because I have almost no idea what you typed.
If you did type "5j + 16 - 12(-9j - 4) - 12j" then your answer would be 133j + 52 I believe. You never put how you would like your problem to be solved, so I simplified.
Step-by-step explanation:
Hope this helps.
