Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
x=9.768
y=6.972
Step-by-step explanation:
For this problem we have to use the trig relationships of cos and sin to figure out the lengths. Cos is equal to adjacent/hypotenuse so we can set it as x/r=.814 and since r is equal to 12 we can do 12 times .814 to get x.
We do a similar process for sin but sin is equal to opposite/hypotenuse so we can set up the equation y/r=.581 and we simply multiply both sides by 12 to get 12*.581 to get y.
Also for future reference adjacent and hypotenuse are based on the angle at use, since ∅ is on the bottom left x is the adjacent side and y is the opposite side.
Answer:
-10
-5
5
Step-by-step explanation:
From the answers given, you probably mean f(x) = x^3 + 10x2 – 25x – 250
The Remainder Theorem is going to take a bit to solve.
You have to try the factors of 250. One way to make your life a lot easier is to graph the equation. That will give you the roots.
The graph appears below. Since the y intercept is -250 the graph goes down quite a bit and if you show the y intercept then it will not be easy to see the roots.
However just to get the roots, the graph shows that
x = -10
x = - 5
x = 5
The last answer is the right one. To use the remainder theorem, you could show none of the answers will give 0s except the last one. For example, the second one will give
f((10) = 10^3 + 10*10^2 - 25*10 - 250
f(10) = 1000 + 1000 - 250 - 250
f(10) = 2000 - 500
f(10) = 1500 which is not 0.
==================
f(1) = (1)^3 + 10*(1)^2 - 25(1) - 250
f(1) = 1 + 10 - 25 - 250
f(1) = -264 which again is not zero
I agree. There can't ever be 2 equal signs in A math problem