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3 years ago

What is the value of g(−3) when g(x)=2x−2 ?

Mathematics

2 answers:

Vikki [24]3 years ago

6 0

Answer:

The answer is -8

Hope this helps :)

nikdorinn [45]3 years ago

3 0

For these types of problems, plug the value inside the ( ) into the (x) of the equation.
g (-3), g (x) = 2x-2
g (x) = 2 (-3) - 2 = -6 - 2 = -8
g (-3) = -8

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Evaluate the expression shown for x = 9.

tatiyna

Answer:

B. 1/2

Step-by-step explanation:

Make 9 an improper fraction, then multiply by -5/6.

-5/6 times 9/1 = -45/6.

-45/6 cannot be simplified, so you make it a mixed number.

-7 1/2.

Add the 7 to -7 1/2 and that cancels out to 1/2

4 0

2 years ago

The art teacher had 1,321 pipe cleaners for a project. She used 477 with the entire fourth grade. A parent donated 2,600 pipe cl

larisa86 [58]

Answer:

3,444

Step-by-step explanation:

The art teacher had 1321 pipe cleaners for a project

She used 477 with the fourth age

A parent donated 2,600 pipe cleaners

Therefore the number of pipe cleaners she have left can be calculated as follows

= 1321-477+2600

= 844 + 2600

= 3,444

4 0

2 years ago

What is $96 spent in 4 hours written as a unit rate in minutes

lara31 [8.8K]

Answer: The unit rate of $96 spent in 4 hours is, $24 per hour.

Step-by-step explanation: To find the unit rate, you will need to write the information as a ratio, $96/4 hours. If you divide 96 by 4 you will get 24. That means this person spends $24 every hour or $24 per hour or $24/1 hour.

3 0

3 years ago

Jenny bought a $50 jacket. If the sales tax rate is 8%, how much tax did she pay?

OlgaM077 [116]

Answer:

54$

Step-by-step explanation:

To get the tax times the number to the percentage
50 * 8% = 4
50 + 4 = 54 $

8 0

1 year ago

The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1

evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\$