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zmey [24]
3 years ago
5

What is the value of g(−3) when g(x)=2x−2 ?

Mathematics
2 answers:
Vikki [24]3 years ago
6 0

Answer:

The answer is -8

Hope this helps :)

nikdorinn [45]3 years ago
3 0
For these types of problems, plug the value inside the ( ) into the (x) of the equation.
g (-3), g (x) = 2x-2
g (x) = 2 (-3) - 2 = -6 - 2 = -8
g (-3) = -8
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The 5 horses on Miranda's farm each eat 20 pounds of feed per day . How many tons of feed do the horses in in 30 days
satela [25.4K]

Answer:

1.5 tons

Step-by-step explanation:

First determine how much feed is eaten per day

5 * 20 lbs = 100 lbs per day

Then multiply by the number of days

30 * 100 = 3000 lbs

But the question asks tons, not lbs

We know there are 2000 lbs in a ton

3000lbs/ 2000lbs per ton = 1.5 tons

7 0
3 years ago
Which graph shows the solution to the inequality |x+3|<2?
rewona [7]

B is the correct answer,

Here's why!

|x+3|<2

case 1 and case 2 states you need to invert it to see which either is

case 1 would be

|-x-3|<2

-x< 5

x>-5

and on the other case

case 2 would be

x+3<2

x<-1

so this means that

B would be your answer!

x>-5 and x<-1

Please mark brainlyist!

6 0
3 years ago
The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle?
frozen [14]

the cathetis is 1 cm

6 0
3 years ago
Pls help, my teacher told me to translate this as an assignment so pls help.
Shtirlitz [24]

Answer:

the first easy assignment for aii the students

the first day of school is go in to be in a while

Step-by-step explanation:

8 0
3 years ago
A lighthouse is located on a small island 5 km away from the nearest point P on a straight shoreline and its light makes six rev
mote1985 [20]

Answer:

The beam of light is moving along the shoreline at a velocity of approximately 196 kilometers per second.

Step-by-step explanation:

The statement is described geometrically in the image attached below by means of a right triangle. All variables are described below:

OP - Minimum distance between lighthouse and the straight shoreline, in kilometers.

PP' - Distance along the straight shoreline, in kilometers.

\theta - Angle of rotation of the lighthouse, in sexagesimal degrees.

To find the rate of change of distance along the straight shoreline (\frac{dPP'}{dt}), in kilometers per minute, we use the following trigonometric relationship:

PP' = OP \cdot \tan \theta (1)

Then, we differentiate this expression in time:

\frac{dPP'}{dt} = OP\cdot \dot \theta \cdot \sec^{2}\theta (2)

Where \dot \theta is the rate of change of the angle of rotation of the lighthouse, in radians per minute.

The angle at the given instant is calculated by (1): OP = 5\,km, PP' = 1\,km

\theta = \tan^{-1} \left(\frac{PP'}{OP} \right)

\theta \approx 11.310^{\circ}

If we know that \dot \theta = 37.699\,\frac{rad}{min}, \theta \approx 11.310^{\circ} and OP = 5\,km, then the rate of change is:

\frac{dPP'}{dt} \approx 196,035\,\frac{km}{min}

The beam of light is moving along the shoreline at a velocity of approximately 196 kilometers per second.

7 0
3 years ago
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