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2 years ago

Which name applies to the angle pair shown below?

Mathematics

2 answers:

alekssr [168]2 years ago

5 0

Answer:

b complementary

Step-by-step explanation:

The two angles add to form a right angle. Two angles that form a right angle, or add to 90 degrees are called complementary.

OLga [1]2 years ago

5 0

Answer:

<em><u>B.) Complementary</u></em>

Step-by-step explanation:

A.) A straight angle is an angle that makes a 180° angle, which is wrong.

B.) A complementary pair is two angles who's sum is 90°. Since in the picture, there is a 90° (you can tell by the little square in it's angle) split in two, it is complementary.

C.) Vertical angles are two angles made opposite by two intersecting lines.

D.) Supplementary angles (2) make a total of 180° when they are added together.

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What is the answer please

Elena L [17]

Hello from MrBillDoesMath!

Answer:

The third choice, 99

Discussion:

I'm not sure what that strange cutout in the parallelogram has to do with the problem but ..... the area of parallelogram is given by (base)(height). In our case, assuming the length ("height') ED = 11 and length AB ("base") = 5 + 4 = 9, the area = 11 * 9 = 99 square centimeter. This is the third choice.

Thank you,

MrB

5 0

3 years ago

Which statements about finding the area of the equilateral triangle are true? Check all that apply.

lara31 [8.8K]

Answer:

The correct options are 1, 2 and 4.

Step-by-step explanation:

The given triangle is an equilateral triangle. All the sides of an equilateral triangle are same. All interior angles are equal with measure 60 degree.

The distance from the center of an equilateral triangle to the midpoint of a side is known as apothem. In the given figure letter a represents the apothem.

Point D is the midpoint of BC,

$b=\frac{BC}{2}=\frac{8.7}{2}=4.35$

Use Pythagorean theorem in triangle COD. So, option 1 is correct.

$OC^2=OD^2+DC^2$

$5^2=a^2+(4.35)^2$

$25=a^2+18.9225$

$a=\pm 2.46526$

$a\approx\pm 2.5$

The distance can not be negative, so the length of the apothem is approximately 2.5 cm. Option 4 is correct.

The line OC bisects the angle C.

$tan(30^{\circ})=\frac{a}{b}$

$\frac{1}{\sqrt{3}=\frac{a}{4.35}$

$a\approx\pm 2.5$

Therefore option 2 is correct.

The perimeter of an equality triangle is

$P=3a=3(8.7)=26.1$

Option 3 is incorrect.

$A=\frac{\sqrt{3}}{4}a^2=\frac{\sqrt{3}}{4}(8.7)^2=32.77$

Option 5 is incorrect.

Therefore options 1, 2 and 4 are correct.

3 0

3 years ago

Read 2 more answers

Solve equations using inverse operations HELP NOW!!

aev [14]

Algebra

The inverse of -9n is dividing by -9.

$n = - 5$

4 0

2 years ago

Read 2 more answers

PLEASE HELP!! I do not understand this. And can you explain it for me when I use it again?

damaskus [11]

Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)
Reflecting
A(0,0,0)

B(0,5,0)
Reflecting
B(0,-5,0)

C(3,5,0)
Reflecting
C(3,-5,0)

D(3,0,0)
Reflecting
D(3,0,0)

b.)
A(0,0,0)
Moving
A(-2,-3,1)

B(0,-5,0)
Moving
B(-2,-8,1)

C(3,-5,0)
Moving
C(1,-8,1)

D(3,0,0)
Moving
D(1,-3,1)

7 0

2 years ago

Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG

qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

Opposite sides are equal and parallel.
Opposite angles are equal to each other.
Consecutive angles are supplementary
The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

5 0

3 years ago