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3 years ago

In the diagram, the parallel lines mand n are cut by the transversal line 1

Mathematics

1 answer:

dybincka [34]3 years ago

8 0

Answer:

Step-by-step explanation:

They are congruent

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A bag contains yellow marbles and blue marbles, 73 in total. The number of yellow marbles is 7 more than 5 times the number of b

Roman55 [17]

Answer:

number of yellow marbles=62.

Step-by-step explanation:

It is given that in a bag there are yellow marbles and blue marbles and the total number of marbles=73.

Let the number of Blue marbles=x, then according to the question, number of yellow marbles will be =5x+7.

Now, Total number of marbles= number of yellow marbles+number of blue marbles.

⇒73=x+5x+7

⇒73-7=6x

⇒66=6x

⇒x=11

Therefore, numberof blue marbles=x=11 and

number of yellow marbles=5x+7=5(11)+7=55+7=62.

8 0

3 years ago

In the triangle below, what is csc θ?

earnstyle [38]

It si cool so basicly u take 5 divide bye 13 times 5

8 0

3 years ago

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Please help :)!!!!!!!!!!!!!!!!!!!!!!

mart [117]

x adds 1 and y subtracts by 6

7 0

3 years ago

What is 1.7 as a fraction?

choli [55]

1.7 as a fraction is 17/10

1.(7) the 7 in the parentheses represents the number after the decimal, which is in the tenths spot. 10 tenths + 7 tenths = 17/10 <-- our answer.

3 0

3 years ago

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Solve The Equation <br> 4x×9y=7<br> 4x-9y=9

hoa [83]

Answer:

$\large\boxed{x=\dfrac{9}{8}-\dfrac{\sqrt{109}}{8},\ y=-\dfrac{1}{2}-\dfrac{\sqrt{109}}{18}}\\or\\\boxed{x=\dfrac{9}{8}+\dfrac{\sqrt{109}}{2},\ y=-\dfrac{1}{2}+\dfrac{\sqrt{109}}{18}}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}4x\times9y=7&(1)\\4x-9y=9&(2)\end{array}\right\\\\(2)\\4x-9y=9\qquad\text{subtract}\ 4x\ \text{from both sides}\\-9y=-4x+9\qquad\text{change the signs}\\9y=4x-9\qquad\text{substitute it to (1)}\\\\4x(4x-9)=7\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\(4x)(4x)+(4x)(-9)=7\\(4x)^2-36x=7\\(4x)^2-2(4x)(4.5)=7\qquad\text{add}\ 4.5^2\ \text{to both sides}\\(4x)^2-2(4x)(4.5)+4.5^2=7+4.5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2$

$(4x-4.5)^2=7+20.25\\(4x-4.5)=27.25\to 4x-4.5=\pm\sqrt{27.25}\\\\4x-\dfrac{45}{10}=\pm\sqrt{\dfrac{2725}{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{2725}}{\sqrt{100}}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25\cdot109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{\sqrt{25}\cdot\sqrt{109}}{10}\\\\4x-\dfrac{45}{10}=\pm\dfrac{5\sqrt{109}}{10}\qquad\text{add}\ \dfrac{45}{10}\ \text{to both sides}\\\\4x=\dfrac{45}{10}\pm\dfrac{5\sqrt{109}}{10}$

$4x=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 4}\\\\x=\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\\\\\text{Put the values of}\ x\ \text{to (2):}\\\\9y=4\left(\dfrac{9}{8}\pm\dfrac{\sqrt{109}}{8}\right)-9\\\\9y=\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}-\dfrac{18}{2}\\\\9y=-\dfrac{9}{2}\pm\dfrac{\sqrt{109}}{2}\qquad\text{divide both sides by 9}\\\\y=-\dfrac{1}{2}\pm\dfrac{\sqrt{109}}{18}$

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3 years ago