It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
Let x be the number of hours ling work on monday.
We know that she worked three more hours on tuesday that in monday, this can be express as :

We also know that in wednesday she worked on more hour than twice the number on mondays, this can be expressed as:

The total number of hours she worked this three days in two more than five the number of hours she worked on monday, this can be express as :

Now , once we have all the expressions we add the expressions of the days and equate them to the total

Now we solve the equation

Therefore , she worked 2 hours on monday.
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1.) expand
3x - 15 - 5x = 25 + 6x
2.) simplify
-2x - 15 = 25 + 6x
3.) add 2x to both sides
-15 = 25 + 6x + 2x
4.) simplify
-15 = 25 + 8x
5.) subtract 25 from both sides
-15 - 25 = 8x
6.) simplify -15 - 25 to -40
-40 = 8x
7.) divide both sides by 8
-40/8 = x
8.) x = -5
Answer:
True
Step-by-step explanation:
First, we need to recognize that

Now, we can try to solve

Multiply each side by 

As we end up with an answer that cannot be true, we know that there is no solution.
Another method to solve this would be graphing the function 
When graphed, it can be seen that there is an asymptote at x=0 meaning that there is no value for x=0.