Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
A) if 18 muffins = 1 box,
1020 muffins = 1020/18 boxes
= 56.67 boxes
So they used 56 full boxes.
b) if 25 cookies = 1 bag
2820 cookies = 2820/25 bags
= 112.8 bags
So they used 112 full bags.
c) the remainders from a and b represent muffins and cookies left over.
Answer:
12/1
Step-by-step explanation:
hope this helped if not sorry
Answer: 1
Explanation: anything to the power of 0 is 1 so if it is x to the power of 0 it would be 1
