Answer:
The cost of the old ball was $100.
Step-by-step explanation:
The cost of the new ball = $300
The new ball has three times the price of his old ball.
So, let the price of the old ball be = x
As per situation, we get the equation:

Dividing both sides by 3:

=> x = 100
Hence, the cost of the old ball was $100.
Combine like terms and then simplify
For this question, you would have to use the midpoint formula.
(X1 +X2 / 2 , Y1 + Y2 / 2)
In other words,
(9 + -3 / 2 , -7 +5 / 2)
(6 / 2 , -2 / 2)
(3 , -1)
Your midpoint is (3, -1)
That looks correct. If your graph let's you scroll upward, double check to see if the line crosses 1 on the x axis. as long as it never touches x=1, you answer is correct
Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
There's no variation among the discussion sections
There's variation among the discussion sections

Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic = 

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.