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zysi [14]
3 years ago
6

6v-6+2(3v+3)=-2(v+9)

Mathematics
1 answer:
ANEK [815]3 years ago
7 0
I’m pretty sure it’s 18, idk search it on google and it will tell u the answer
You might be interested in
8 to power -2 multiplied by a to power of 7
levacccp [35]
<span> (8^ -2)(4^4)(16^ -1)

</span>
<span>a^-x=(1/a^x)

</span>
<span> (4^4)/((8^2)(16))

"NOTE"  </span><span>16^1=16

</span>
<span>4^4=256

 8^2=64

256/((64)(16))=1/4
</span>
<span>convert 1/4 to a power of two
</span>
<span>(4) is 2

 1/4=1/(2^2)
</span>
<span>1^2=1

 (1/2)^2=(1/4)

</span>
<span>1/2 to the power of 2 is the answer

It would look like this

1/2²
</span>
8 0
3 years ago
8. Which situation BEST represents an inverse variation ?
Mademuasel [1]

The correct answer is option D.

Explanation:

Inverse variation implies negative relationship. This means that as one of the quanties being compared increases the other decreases and vice versa..

4 0
1 year ago
PLEASE HELP!!!!!!!!!
Inessa05 [86]
It’s a 60 degree angle :)
6 0
3 years ago
How could I solve this ? 14 + k = 3k -2
Diano4ka-milaya [45]

Answer:

14 + k = 3k - 2

    - k    - k

14 = 2k - 2

+2         +2

16 = 2k

8 = k

Step-by-step explanation:

6 0
3 years ago
If the confidence level is 90%, find the Margin of sampling error. The population is normally distributed, the sample size is 15
charle [14.2K]

Answer:

ME = 1.761* \frac{5}{\sqrt{15}}=2.273

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 75 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5 represent the sample standard deviation

n=15 represent the sample size  

Solution to the problem

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,14)".And we see that t_{\alpha/2}=1.761

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    

And if we replace the values we got:

ME = 1.761* \frac{5}{\sqrt{15}}=2.273

6 0
3 years ago
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