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2 years ago

Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel.

Mathematics

2 answers:

Vinvika [58]2 years ago

5 0

What am I supposed to be answering here?? How old Daniel is, or how old Kevin is?

viktelen [127]2 years ago

4 0

We have 3 + d - 2 = 4d - 8;
then - d + 1 = 4d - 8;
9 = 3d:
d = 3.
Finally, k = 6 years.

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nordsb [41]

Answer:

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Step-by-step explanation:

To find the common difference, take the second term and subtract the first term

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Check by subtracting the second term from the third term

-9 - (-2) = -9+2 = -7

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nataly862011 [7]

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Step-by-step explanation:

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2 years ago

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Westkost [7]

Answer: $x(2x^2+4x-1)$

Step-by-step explanation:

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2 years ago

In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho

Mekhanik [1.2K]

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be $\frac{42}{7} C^{\circ}$ .

Additionally, this can be solved by equations:

$\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}$

$1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} = x$

By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

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