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const2013 [10]
3 years ago
15

Point A is located at (-4, -13). Point B is located at (-4, 3). What is the distance between point A

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Answer:

the distance is 16

Step-by-step explanation:

Hi there!

We are given point A (-4,-13) and point B (-4,3). We need to find the distance between those two points

the distance formula is given as \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2} where (x_{1},y_{1}) and (x_{2}, y_{2}) are points

we are given 2 points, which is what we need for the formula. However, let's label the values of the points to avoid any confusion

x_{1}=-4

y_{1}=-13

x_{2}=-4

y_{2}=3

now substitute those values into the formula. Remember: the formula uses SUBTRACTION.

\sqrt{(-4--4)^2+(3--13)^2}

simplify

\sqrt{(-4+4)^2+(3+13)^2}

now add the values inside the parenthesis that are under the radical

\sqrt{(0)^2+(16)^2}

raise everything under the radical to the second power

\sqrt{0+256}

add under the radical

\sqrt{256}

now take the square root of 256

\sqrt{256}=16

so the distance between point A and point B is <u>16</u>

Hope this helps! :)

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Answer:

\left[\begin{array}{cc}2&8\\5&1\end{array}\right]

Step-by-step explanation:

The <em>transpose of a matrix </em>M^T is one where you swap the column and row index for every entry of some original matrix M. Let's go through our first matrix row by row and swap the indices to construct this new matrix. Note that entries with the same index for row and column will stay fixed. Here I'll use the notation p_{i,j} and p^T_{i,j} to refer to the entry in the i-th row and the j-th column of the matrices P and P^T respectively:

p_{1,1}=p^T_{1,1}=2\\p_{1,2}=p^T_{2,1}=5\\p_{2,1}=p^T_{1,2}=8\\p_{2,2}=p^T_{2,2}=1\\

Constructing the matrix P^T from those entries gives us

P^T=\left[\begin{array}{cc}2&8\\5&1\end{array}\right]

which is option a. from the list.

Another interesting quality of the transpose is that we can geometrically represent it as a reflection over the line traced out by all of the entries where the row and column index are equal. In this example, reflecting over the line traced from 2 to 1 gives us our transpose. For another example of this, see the attached image!

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