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kondor19780726 [428]
3 years ago
9

We can describe 3x-2 as an expression how can we describe the parts of the expression that the arrows point to?

Mathematics
1 answer:
Oksanka [162]3 years ago
8 0

Answer:

If the arrow is pointing to the -2, that’s the constant.

If the arrow is pointing at x, that’s the variable.

If the arrow is pointing at 3, that’s the coefficient.

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5n = 8n + 30<br> help me pleaseeeeee
fgiga [73]
To find n
1. Subtract 8n from both side to get -3n=30
2. Divide both sides by -3 to get n=-10
3 0
3 years ago
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A concession stand at a baseball game sells 3 apples for $2.00.How can you find the cost for 10 apples?
ElenaW [278]

Answer: 3 divided by 2 = 1.50

1.50×10=15

Step-by-step explanation:

8 0
2 years ago
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What is 8/40 in simplest form?
tensa zangetsu [6.8K]
Divide 8 by 8= 1
divide 40 by 8=5
1/5
3 0
3 years ago
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. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
What is the area of the shape?
marshall27 [118]

Step-by-step explanation:

hello,

the shape is a right trapezium.

you use the following formula:

area of a trapezium = ½ × sum of parallel sides× height.

or simply,

a = ½ ( a + b ) h

where a and b are the parallel sides

and h is the height.

thus,

a = ½ × ( 4 + 6 )× 4

a = ½ ( 10 ) × 4

a = 5 × 4

a = 20

have a great day! au revoir !

6 0
2 years ago
Read 2 more answers
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