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3 years ago

I have a few Algebra problems that I have no clue how to solve. Help would be greatly appreciated!

Mathematics

1 answer:

DENIUS [597]3 years ago

8 0

I'm just going to number all of the problems so life get's easier. :D

JSYK: A negative and a negative multiplied make a positive. Like that... a + and a + is +. And a + and a - is a - .

1) 37= -3+5(k+6)

1. Use Distributive Property to take out the parentheses. Positive 5 times k and then 5 times 6... 37=-3+5k+30. 2. Take all the normal number to either side of the equal sign. 37-3-30=5k 3. Subtract all the numbers on the left side.... 4=5k 4. Now divide both sides by 5 to isolate k.... k=[tex] \frac{4}{5} [/text] ----------------------------------------------------------------------------------------------- 2) -2= -(w-8)

1. Use Distributive Property to take out the parentheses. "Distribute the negative sign... -2= -w+8 2. Put the -w to the left side and the -2 to the right side, so that the variable won't be negative... w= 2+8 3. Add everything on the right side... w= 10 ----------------------------------------------------------------------------------- 3) 42= 8x+13x

1. Since both of the numbers have the same variables (in this case, x), add them up... 42=21x 2. Divide each side by 21 to isolate x... x=42 ------------------------------------------------------------------------------------ 4) 8= 8c-4(c+8)

1. Use Distributive Property. Multiply negative 4 with c and 8... 8=8c-4c-32 2. On the right side, 8 and 4 both have the same variable, c , solve it!...8=4c-32 3. Put -32 to the left side... 8+32=4c 4. Add on the left... 40=4c 5. Divide both sides by 4 to isolate c... c=10 ------------------------------------------------------------------------------------- 5) -11-5z= 6(5z+4) 1. Use Distributive Property; multiply positive 6 with 5z and 4... -11-5z=30z+24 2. Bring -5z to the right and positive 24 to the left... -11-24= 30z+5z 3. Subtract the integers on the left and add the numbers with same variable on the right... -35=35z 4. Divide both sides by 35 to isolate z... z= -1 ----------------------------------------------------------------------------- 6) 0= -5y-2y

1. Subtract the negative number with the same variable, y ... 0= -7y 2. Divide both sides by -7, to isolate y... y=0

And for the last two, I don't know either... my apologies! I hope my answers help! :D

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Approximate the zeros of the function. Round to the nearest tenth if necessary. f(x) = 4x^2 + 4x - 35. Explain each step on how

svet-max [94.6K]

4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5

I don't see any rounding necessary in this case.

when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5

2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.

if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.

I hope this makes sense to you.

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3 years ago