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koban [17]
4 years ago
11

I have a few Algebra problems that I have no clue how to solve. Help would be greatly appreciated!

Mathematics
1 answer:
DENIUS [597]4 years ago
8 0

I'm just going to number all of the problems so life get's easier. :D

JSYK: A negative and a negative multiplied make a positive. Like that... a + and a + is +. And a + and a - is a - .


1) 37= -3+5(k+6)

1. Use Distributive Property to take out the parentheses. Positive 5 times k and then 5 times 6... 37=-3+5k+30. 2. Take all the normal number to either side of the equal sign. 37-3-30=5k 3. Subtract all the numbers on the left side.... 4=5k 4. Now divide both sides by 5 to isolate <em>k</em>.... k=[tex] \frac{4}{5} [/text] ----------------------------------------------------------------------------------------------- 2) -2= -(w-8)

1. Use Distributive Property to take out the parentheses. "Distribute the negative sign... -2= -w+8 2. Put the -w to the left side and the -2 to the right side, so that the variable won't be negative... w= 2+8 3. Add everything on the right side... w= 10 ----------------------------------------------------------------------------------- 3) 42= 8x+13x

1. Since both of the numbers have the same variables (in this case, x), add them up... 42=21x 2. Divide each side by 21 to isolate <em>x</em>... x=42 ------------------------------------------------------------------------------------ 4) 8= 8c-4(c+8)

1. Use Distributive Property. Multiply <em>negative</em> 4 with c and 8... 8=8c-4c-32 2. On the right side, 8 and 4 both have the same variable, <em>c </em>, solve it!...8=4c-32 3. Put -32 to the left side... 8+32=4c 4. Add on the left... 40=4c 5. Divide both sides by 4 to isolate <em>c</em>... c=10 ------------------------------------------------------------------------------------- 5) -11-5z= 6(5z+4) 1. Use Distributive Property; multiply positive 6 with 5z and 4... -11-5z=30z+24 2. Bring -5z to the right and positive 24 to the left... -11-24= 30z+5z 3. Subtract the integers on the left and add the numbers with same variable on the right... -35=35z 4. Divide both sides by 35 to isolate <em>z</em>... z= -1 ----------------------------------------------------------------------------- 6) 0= -5y-2y

1. Subtract the negative number with the same variable, <em>y</em> ... 0= -7y 2. Divide both sides by -7, to isolate <em>y</em>... y=0

And for the last two, I don't know either... my apologies! I hope my answers help! :D

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weeeeeb [17]

Answer:

3768

Step-by-step explanation:

The question is asking for the volume of the "cylinder" straw.

1cm = 10mm

30cm = 300mm

Volume of a cylinder = \pi r^2h

The radius is half of the diameter = 4/2 = 2

Radius squared is 4

Height is 300mm

1200mm * 3.14 = 3768

I am not very sure, since I am not that familiar with cylinders. Sorry if this is wrong.

Hope this helps :)

Have a great day!

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2 years ago
The ratio of 5 red trucks / 9 white trucks
antoniya [11.8K]

Answer:

5 to 9            5:9            5/9

Step-by-step explanation:

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3 years ago
Rate and Ratio Sipho paid 605,50 for 70litres of petrol.What did the petrol cost per litre.​
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2 years ago
Could someone help me for this?
lina2011 [118]

Answer:

x = - \frac{5}{3} , x = \frac{5}{2}

Step-by-step explanation:

to find the points of intersection equate the 2 equations , that is

7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )

6x² - 5x - 25 = 0 ← factor the quadratic on left side

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × - 25 = - 150 and sum = - 5

the factors are - 15 and + 10

use these factors to split the x- term

6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )

3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term

(2x - 5)(3x + 5) = 0

equate each factor to zero and solve for x

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - \frac{5}{3}

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

3 0
2 years ago
(03.01 LC)<br><br> What is the length of leg y of the right triangle? (1 point)
EastWind [94]

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

  • 10
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  • 26

We need to use the Pythagorean Theorem, where h=26 and x=24,

h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10

Therefore, the right answer is A. The length of the missing leg is 10 units.

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3 years ago
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