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3 years ago

2/3y - 2/5 = 5 and please show work Algebra

Mathematics

2 answers:

meriva3 years ago

6 0

Find the LCD and multiply both sides by 15 to get 10y-6=75
Add 6 to 76 to get 10y=81
Y =81/10

Travka [436]3 years ago

3 0

2/3y-2/5=5

We move all terms to the left:

2/3y-2/5-(5)=0

Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R

determiningTheFunctionDomain

2/3y-5-2/5=0

We calculate fractions

There is no solution for this equation

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I need help please!!!

slamgirl [31]

Answer:

use desmos

Step-by-step explanation:

Desmos is a graphing app and is really good and do like my post please

6 0

3 years ago

Given that (5,-8) is on the graph of f(x), find

My name is Ann [436]

Answer:

The corresponding point for the function f(x + 2) is (3 , -8)

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) translated horizontally to the right by h units,

then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left by h units,

then the new function g(x) = f(x + h)

* Lets solve the problem

- There is a graph of f(x)

- Point (5 , -8) lies on the graph of f(x)

- The graph of f(x) change to f(x + 2)

∵ f(x) ⇒ f(x + 2)

∵ If the function f(x) translated horizontally to the left by h units,

then the new function g(x) = f(x + h)

∴ f(x) translated horizontally 2 units to the left

∴ Any point on the graph its x-coordinate translated 2 units

to the left

∴ The x-coordinate of any point on the graph is subtracted by 2

∵ Point (5 , -8) lies on the graph

∴ Its corresponding point is (5 - 2 , -8) = (3 , -8)

* The corresponding point for the function f(x + 2) is (3 , -8)

7 0

3 years ago

51^7 -51^6 by 25 __*25

BartSMP [9]

Answer:

Step-by-step:

51⁷-51⁶ = 51⁶(51-1) = 51⁶(50)

50 is divisible by 25, so 51⁷-51⁶ is divisible by 25.

7 0

3 years ago

Read 2 more answers

Find 51% of 140, Round to the nearest tenth if necessary.

viktelen [127]

Answer:71.4

Step-by-step explanation:140*51%

7 0

3 years ago

Read 2 more answers

Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z

Oliga [24]

Part a)

Given the expression

$54m^3n\:+\:81m^4n^2$

Apply exponent rule: $a^{b+c}=a^ba^c$

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn$ ∵ $m^4n^2=m^3mnn$

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

$=2\cdot \:27m^3n+3\cdot \:27m^3mnn$

Factor out the common term: 27m³n

$=27m^3n\left(2+3mn\right)$

Therefore,

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)$

Part B)

Given the expression

$15x^2y^3z+25x^3y^2z+35x^2y^2z$

Apply exponent rule: $a^{b+c}=a^ba^c$

$15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z$

Rewrite as

$=3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z$

Factor out common term 5y²x²z

$=5y^2x^2z\left(3y+5x+7\right)$

Therefore,

$15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)$

8 0

3 years ago